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mr_godi [17]
3 years ago
11

8 x(11-3) + 9 with and exponent of 2

Mathematics
2 answers:
lesya692 [45]3 years ago
6 0

Answer:

73

Step-by-step explanation:

first u have to subtract 11 and 3 with is 8 and then you have to multiply 8 times 8 which is 64 aqnd then plus 9 and there u get 73

Keith_Richards [23]3 years ago
5 0

Answer:

PEMDAS

11-3= 8 x 8=64 + 9= 73 with and exponent of 2

Step-by-step explanation:

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Endpoints of segment MN have coordinates (0, 0), (5, 1). The endpoints of segment AB have coordinates (1 1/22 , 2 1/4 ) and (−2
Nana76 [90]

Answer: k=18\dfrac{8}{11}.

Step-by-step explanation:

If a line passing through two points, then

Slope=\dfrac{y_2-y_1}{x_2-x_1}

Endpoints of segment MN have coordinates (0, 0) and (5, 1).

Slope of MN =\dfrac{1-0}{5-0}=\dfrac{1}{5}

The endpoints of segment AB have coordinates \left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right) and  \left(-2\dfrac{1}{4} , k\right).

A=\left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right)=\left(\dfrac{23}{22} ,\dfrac{9}{4}\right)

B=\left(-2\dfrac{1}{4} , k\right)=\left(-\dfrac{9}{4} , k\right).

Slope of AB =\dfrac{k-\frac{9}{4}}{-\frac{9}{4}-\dfrac{23}{22}}

=\dfrac{\frac{4k-9}{4}}{\frac{-99-46}{44}}

=\dfrac{4k-9}{4}\times \dfrac{44}{-145}

=4k-9\times \dfrac{11}{-145}

=\dfrac{44k-99}{-145}

Product of slopes of two perpendicular segments is -1.

Slope of MN × Slope of AB = -1

\dfrac{1}{5}\times \dfrac{44k-99}{-145}=-1

\dfrac{44k-99}{-725}=-1

44k-99=725

44k=725+99

k=\dfrac{824}{44}

k=\dfrac{206}{11}

k=18\dfrac{8}{11}

Therefore, the value of k is k=18\dfrac{8}{11}.

8 0
3 years ago
Read 2 more answers
Look at the histogram below which data set could be represented by the histogram
Anon25 [30]

Answer:

Option 4 is correct

Step-by-step explanation:

Here, we want to select from the options, the dataset that is represented on the histogram

From what we have in the question, there is a range from 60 to 100

Also, there are no terms between 70 and 80

option 1 is wrong as we can see terms between 70 and 80

option 2 is also wrong for this reason

option 3 is incorrect ; looking at the frequency, the numbers between 60 and 70 should be 5 only and we have 6 in that set

Option 4 is the correct answer

4 0
3 years ago
If you answer this you will get 69 points but please answer asap
spin [16.1K]

Answer:

I think the answer for the first one is 3 I am not sure about the second one

3 0
3 years ago
Given that it was less than 80º on a given day, what is the probability that it also rained that day? 0.3 0.35 0.65 0.7
eimsori [14]

The probability that it also rained that day is to be considered as the 0.30 and the same is to be considered.

<h3>What is probability?</h3>

The extent to which an event is likely to occur, measured by the ratio of the favorable cases to the whole number of cases possible.

The probability that the temperature is lower than 80°F and it rained can be measured by determining the number at the intersection of a temperature that less than 80°F and rain.

So, This number is 0.30.

Hence, we can say that it was less than 80°F on a given day, the probability that it also rained that day is 0.30.

To learn more about the probability from the given link:

brainly.com/question/18638636

The above question is incomplete.

The conditional relative frequency table was generated using data that compared the outside temperature each day to whether it rained that day. A 4-column table with 3 rows titled weather. The first column has no label with entries 80 degrees F, less than 80 degrees F, total. The second column is labeled rain with entries 0.35, 0.3, nearly equal to 0.33. The third column is labeled no rain with entries 0.65, 0.7, nearly equal to 0.67. The fourth column is labeled total with entries 1.0, 1.0, 1.0. Given that it was less than 80 degrees F on a given day, what is the probability that it also rained that day?

#SPJ4

7 0
2 years ago
Please help it will be every helpful
jeka94

I don't know what to do but I think it is #1

3 0
3 years ago
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