Question

PLZ HELP!!!! WILL GIVE BRAINLIEST + WORTH 10 POINTS!!! THX!!!!

Answer 1

Answer:

I got this answer hope works...

Answer 2

Answer:

4

Step-by-step explanation:

$((3^{8})(2^{-5})(9^{0}))^{-2} ((2^{-2}/3^{3}))^{4}(3^{28})$=

((6561)x(2^{-5})x(9^{0}))^{-2}x((2^{-2}/3^{3}))^{4}(3^{28})=

(6561)x(1/32)x(9^{0}))^{-2}x((2^{-2}/3^{3}))^{4}(3^{28})=

(6561/32)x(9^{0}))^{-2}x((2^{-2}/3^{3}))^{4}(3^{28})=

(6561/32)x(1)^{-2}x((2^{-2}/3^{3}))^{4}(3^{28})=

(6561/32)^{-2}x((2^{-2}/3^{3}))^{4}(3^{28})=

(1024/43046721)x((2^{-2}/3^{3}))^{4}(3^{28})=

(1024/43046721($\frac{1}{4}$/3^{3})^{4}(3^{28})=

(1024/43046721($\frac{1}{4}$/27)^{4}(3^{28})=

(1024/43046721(1/108)^{4}(3^{28})=

(1024/43046721(1/136048896)(3^{28})=

(4/22876792454961)x(3^{28})=

4/22876792454961)x(22876792454961)=

4

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If this answer is correct, please make me Brainliest.