The letter S in the alphabet does not have any lines of symmetry. Therefore, the answer to this question is: Zero (0). This is because letter S is not symmetrical when it is cut or divided into 2 parts.
So you can use substitution...which is where you have Y all alone on one side of your equation and then plug it in to the other equation...2x-5=-3x+10 and you.solve for X. So x= 3. Then plug 3 into one of the original equations... Y=2(3)+5. So Y= 11.
0.10d + 0.25q = 3.55
q = d + 3
0.10d + 0.25(d + 3) = 3.55
0.10d + 0.25d + 0.75 = 3.55
0.10d + 0.25d = 3.55 - 0.75
0.35d = 2.80
d = 2.80/0.35
d = 8.....8 dimes
q = d + 3
q = 8 + 3
q = 11 <=== 11 quarters
Y=3x-5
y-3x=-5
Times 2 from both side
y(2)-3x(2)=-5(2)
2y-6x=-10
Times negative from both side
(-)2y-6x(-)=(-)-10
-2y+6x=10
or
6x-2y=10
6x=2y+10
6x-2y=10
Furthermore, we see that both equation have the same 6x-2y=10 which means that both of them have infinity solutions, not a solution. Hope it help!
9/3 =3
(X+7)^2/ (x+7) = x+7
1/x-1
3(x+7)/x-1
3x+21/x-1
