Answer:
0.31932773109
Step-by-step explanation:
- Set it up
- Move the decimal point one place to the right for both of them
- Then, do the long division
- Keep adding zeros at the end until you have your answer
- You can round it to 0.32 if you want
The Prove that two non-zero vectors are collinear if and only if one vector is a scalar multiple of the other is given below.
<h3>What are the proves?</h3>
1. To know collinear vectors:
∧ ⁻a ║ ⁻a
If ⁻b = ∧ ⁻a
then |⁻b| = |∧ ⁻a|
So one can say that line ⁻b and ⁻a are collinear.
2. If ⁻a and ⁻b are collinear
Assuming |b| length is 'μ' times of |⁻a |
Then | 'μ' ⁻a| = | 'μ' ⁻a|
So ⁻b = 'μ' ⁻a
Learn more about vectors from
brainly.com/question/25705666
#SPJ1
Answer:
Answer is D
Step-by-step explanation:
First use sine to figure out x
so "sin(31) = 12 ÷ x"
mulitply both sides by x and you get "x * sin(31) = 12"
divide both side by sin(31) so you get "x = 12 ÷ sin(31)"
after plugging it in a calculator, you get 23.2992 and just rounf to the nearest tenth and you get 23.3
$6.75 Because 3/8 x $18.00 is $6.75
Answer:
First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)
To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
x(x+4)(x-2)=0
x=0 x=-4 x=2
So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)
And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
Plugging in a -5 gets us -35
-1 gets us 9
1 gets us -5
3 gets us 21
So now you know end behavior, zeroes, and signs of intervals
Hope this helps
