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Ivahew [28]
3 years ago
5

F(x)=3x^2 how do I graph the function​

Mathematics
1 answer:
wariber [46]3 years ago
7 0

Answer:

don't now

Step-by-step explanation:

i am sorry I don't know I am only there for points

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WRITE THE SOLUTION TO THE FOLLOWING SYSTEMS<br> HURRY ILL GIVE BRAINLIEST!!!!!!!
Virty [35]

Answer:

1)     (2,4)

2)    (5,-2)

Step-by-step explanation:

those are the points at which the lines cross making them the solutions to the equations

4 0
3 years ago
The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 oun
Ugo [173]

Answer: A) .1587

Step-by-step explanation:

Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.

i.e. \mu=12.30 and \sigma=0.20

Let x denotes the amount of soda in any can.

Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.

Then, the probability that a randomly selected can will need to go through the mentioned process =  probability that a randomly selected can has more than 12.50 ounces of soda poured into it =

P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587

Hence, the required probability= A) 0.1587

6 0
3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0
3 years ago
van purchased a dvd player on sale. the initial price was $175.90. the price after the discount was $141.37. what was the percen
Inessa [10]

Answer: that would be 19.26%

Step-by-step explanation: because it is

6 0
3 years ago
What is the property of the equation 3x+5 - 5 = 20-5
Shalnov [3]

Answer:

x=5

Step-by-step explanation:

We simplify the equation to the form, which is simple to understand

3x+5-5=20-5

We move all terms containing x to the left and all other terms to the right.

+3x=+20-5-5+5

We simplify left and right side of the equation.

+3x=+15

We divide both sides of the equation by 3 to get x.

x=5

6 0
3 years ago
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