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2 years ago

Need help ASAP help please

Mathematics

1 answer:

galben [10]2 years ago

6 0

Answer:

24 miles

Step-by-step explanation:

2.5 inches represents 15 miles,

so 1 inch must represent 15/2.5 = 6 miles.

Since the cities are 4 inches apart on map, they will be 6*4 = 24 miles apart in actual.

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2x+4y=16 what is the slope intercept form

Eva8 [605]

Since slope intercept is y=mx+b, you first want to get rid of the 2x by subtracting it from both sides. after, you should end up with 4y=16-2x or 4y=-2x+16, they both are the same, but some teachers might prefer the slope first. after that, you want to get the y alone, so you divide everything by 4. you should end up with the slope intercept form being y=-2/4x+4, simplified to y=-1/2x+4.

3 0

3 years ago

While shopping for clothes Tracy spent $38 less than three times what Daniel spent right and solve an equation to find how much

Gnom [1K]

Answer:

y=3x-38

Step-by-step explanation:

We know that Tracy spent $38 in less than 3 times than what Daniel spent. Given this information we can put our eqaution together.

Y=3x-38

Hope this helps! :)

6 0

3 years ago

An employer has a staff of eighty actuaries, ten of whom are student actuaries. A student actuary is allowed a total of ten week

sergiy2304 [10]

Answer:

0.1111

Step-by-step explanation:

From the given information;

Number of staffs in the actuary = 80

Out of the 80, 10 are students.

i.e.

P(student actuary) = 10/80 = 0.125

number of weeks in a year = 52

off time per year = 10/52 = 0.1923

P(at work || student actuary) = (50 -10/52)

= 42/52

= 0.8077

P(non student actuary) = (80 -10)/80

= 70 / 80

= 0.875

For a non-student, they are only eligible to 4 weeks off in a year

i.e.

P(at work | non student) = (52-4)/52

= 48/52

= 0.9231

∴

P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)

P(at work) = (0.125 × 0.8077) + ( 0.875 × 0.9231)

P(at work) = 0.1009625 + 0.8077125

P(at work) = 0.90868

Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)

P(he is a student) = (0.125 × 0.8077) ÷ 0.90868

P(he is a student) = 0.1009625 ÷ 0.90868

P(he is a student) = 0.1111

5 0

2 years ago

D)) The ratio of the monthly income and expenditure of Sunayana is 5 : 3. If she

Gnom [1K]

Answer:

Sunayana's income is ₹25000 and expenditures are ₹15000.

Step-by-step explanation:

Let i denote the monthly income and e denote the expenditures.

We know that the ratio of the monthly income to expenditure is 5:3. So, we can write the following proportion:

$\frac{i}{e}=\frac{5}{3}$

Let's multiply both sides by e. This yields:

$i=\frac{5}{3}e$

We know that when the income is <em>increased</em> by 5000 and the expenditures are <em>decreased </em>by 3000, the new ratio is 5:2. So, we can write the following proportion:

$\frac{i+5000}{e-3000}=\frac{5}{2}$

Let's multiply both sides by $(e-3000)$ :

$i+5000=\frac{5}{2}(e-3000)$

Since we know that $i=\frac{5}{3}e$ , substitute:

$\frac{5}{3}e+5000=\frac{5}{2}(e-3000)$

So, let's solve for the expenditures. Distribute the right:

$\frac{5}{3}e+5000=\frac{5}{2}e-7500$

Subtract $\frac{5}{2}e$ from both sides:

$-\frac{5}{6}e+5000=-7500$

Subtract 5000 from both sides:

$-\frac{5}{6}e=-12500$

Multiply both sides by -6/5. So, the expenditures are:

$e=\text{Rs }15000$

We can use the original ratio to find Sunayana's income:

$i=\frac{5}{3}e$

Substitute 15000 for e. Evaluate:

$i=\frac{5}{3}(15000)=\text{Rs }25000$

So, Sunayana's income is ₹25000 and expenditures are ₹15000.

And we're done!

Edit: Wrong currency, sorry about that!

3 0

3 years ago

Read 2 more answers

Factor the following polynomial written in standard form. B^2-14B+49

Vladimir79 [104]

After factoring $B^2-14B+49$ we get $(B-7)(B-7)$

Step-by-step explanation:

We need to factorize the polynomial:

$B^2-14B+49$

Factorization is done by breaking the middle term such that the sum is equal to the middle value of polynomial and product is equal to product of first and last term in the polynomial.

So, Factorizing:

$B^2-14B+49\\=B^2-7B-7B+49\\=B(B-7)-7(B-7)\\=(B-7)(B-7)$

So, After factoring $B^2-14B+49$ we get $(B-7)(B-7)$

Keywords: Factorization, Factors

Learn more about factors at:

#learnwithBrainly

8 0

3 years ago