2 years ago

What is the sum of all the terms in the 10th row of Pascal's Triangle

Mathematics

1 answer:

pantera1 [17]2 years ago

3 0

Look up an image of the triangle, and you can see the sum of 2048.

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4/23+square root of 11

creativ13 [48]

The answer i got is 3.5 rounded

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2 years ago

If you triple the amount of ground ginger to make more pies, how much nutmeg should you use to keep the recipe proportional

klemol [59]

If you triple the ginger, to be able to keep proportion, you would need triple the nutmeg as well.

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3 years ago

Factor completely: −2x3 + 6x2

Pavel [41]

Correct answer is C.

$-2x^3+6x^2 \\-2x^2x+2x^23 \\2x^2(-x+3) \\2x^2(-(x-3)) \\-2x^2(x-3)$

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3 years ago

Which are solutions of the equation x2 - 16 = 0? Check all that apply.

Maurinko [17]

Last one
Because you have to substitute it
So you do X times 2 - 16 = 0
And the only X that works is the last one cause 8 X 2 = 16 and 16 -16=0

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2 years ago

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

hoa [83]

Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

$b^2-4ac=(-7)^2-4(2)(-9)=49+72>0$

So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

5 0

2 years ago

Read 2 more answers