If you wanted an output of 7 for the rule y = -x + 4, what would you need as an input?

1 answer:

6 0

Y is your output, so y=7. Now you have 7=-x+4. You then would subtract 4 from both sides, leaving you with 3=-x. Then divide -1 from both sides so you have x=-3. Your answer is -3.

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Can someone help me?<br> (A) 1.5<br> (B) 3<br> (C) 4.5<br> (D) 6

zhenek [66]

Find the horizontal distance of 230 and find the Vertical distance , which is where the black dot is located.

The black dot is on 49 inches.

Now find the vertical distance f the black line at horizontal 230: This is on 47.5.

The difference between the two is : 49 - 47.5 = 1.5

The answer would be A. 1.5

6 0

3 years ago

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Max wakes up at 7:00am. It take him 10 minutes to get dressed, and 5 minutes to eat breakfast. The bus will pick up max at 7:40a

irinina [24]

Note: I will be using the information in your attachment to answer the question.
Add the minutes to the initial time: 7:00 + 10 minutes + 7 minutes + 5 minutes = 7:22
He will be ready to board the bus at 7:22.
Subtract this time from the time the bus is schedule to pick him up: 7:40 - 7:22 = 18
Max will have 18 minutes before the bus picks him up.

3 0

3 years ago

18. Determine the common difference, the fifth term, and the sum of the first 100 terms of the following sequence:

Ksenya-84 [330]

$a_1=1,\ a_2=2.5,\ a_3=4,\ a_4=5.5,\ ...\\\\a_2-a_1=2.5-1=1.5\\a_3-a_2=4-2.5=1.5\\a_4-a_3=5.5-4=1.5\\a_{n+1}-a_n=1.5=constans\\\\\text{It's an arithmetic sequence with}\\a_1=1,\ \boxed{d=1.5}\\\\a_n=a_1+(n-1)d\to a_n=1+(n-1)(1.5)=1+1.5n-1.5\\\\a_n=1.5n-0.5\\\\a_5=1.5(5)-0.5=7.5-0.5=7\\\boxed{a_5=7}\\\\\text{The formula of a Sum of the First n Terms of an Arithmetric Sequence:}\\\\S_n=\dfrac{2a_1+(n-1)d}{2}\cdot n\\\\\text{We have:}\\a_1=1,\ d=1.5,\ n=100\\\\\text{Substitute}$

$S_{100}=\dfrac{(2)(1)+(100-1)(1.5)}{2}\cdot100=\dfrac{2+(99)(1.5)}{1}\cdot50\\\\=(2+148.5)\cdot50=150.5\cdot50=7,525\\\\\boxed{S_{100}=7,525}\\\\Answer:\\the\ common\ difference:\ d=1.5\\the\ fifth\ term:\ a_5=7\\the\ sum\ of\ first\ 100\ terms:\ S_{100}=7,525$