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3 years ago

If you wanted an output of 7 for the rule y = -x + 4, what would you need as an input?

1 answer:

6 0

Y is your output, so y=7. Now you have 7=-x+4. You then would subtract 4 from both sides, leaving you with 3=-x. Then divide -1 from both sides so you have x=-3. Your answer is -3.

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Which is defined using the undefined terms point and line

____ [38]

Answer:

It's a ray because it has a point and one line that goes on in a direction.

Step-by-step explanation:

5 0

2 years ago

A computer programm contains one error.in order to find the error, we split the program in to blocks and test 2 of them,selected

kolezko [41]

If the E(X) = 1 then that means it has a 100% which is incorrect.
Each block has an equal probability to contain the error so 1/3 because you choose 2/6.

5 0

2 years ago

Are the graphs of the lines in the pair parallel? Explain. <br> y = 3/7x+ 11 –3x + 7y = 13

ankoles [38]

Remember that parallel lines have the same slope.

y=3/7x+11 (in slope intercept form already)

-3x+7y=13 (standard form)

Add 3x to both sides, giving you 7y=3x+13, divide by 7 on both sides, giving

y=3/7x+13/7

Since both equations' slopes' are the same, their graphs will be parallel.

7 0

2 years ago

The sum of the diagonals of a rhombus is 5√2.

Alex

Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
$= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC$
$= \frac{1}{2} BD (AO + OC)$
$\frac{1}{2} BD \times AC$

$So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}$
$BD \times AC = 8$
$Now, AC + \: BD = 5 \sqrt{2}$

Squaring both sides, we get
$AC {}^{2} + BD {}^{2} + 2 AC.BD =50$
$AC {}^{2} + BD {}^{2} + 2 \times 8 = 50$
$AC {}^{2} + BD {}^{2} = 50 - 16$
$AC {}^{2} + BD {}^{2} = 34$

In △AOB, we have
$OA {}^{2} + OB {}^{2} =AB {}^{2}$
$( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}$
$\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}$
$AC {}^{2} + BD {}^{2} = 4 AB {}^{2}$
$34 = 4 AB {}^{2}$

Square rooting both sides
$\sqrt{34} = 2 AB$
$Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units$ .

Hope it helps!

7 0

3 years ago

A car valued at $32,000, depreciates at 9% per year. What is the value of the car after two years?

Leokris [45]

Answer: $26,240

Step-by-step explanation: hope it helps

8 0

2 years ago

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