Answer:
The solution is 0, 90 molal. See the explanation below, please
Explanation:
Molality is defined as moles of solute in 1 kg of solvent (1000 grams). The following three simple rule must be performed:
We calculate the weight of 1 mol of CaCl2
Weight Ca =40, 078 g
Weight Cl= 35, 453 g
Weight of 1 mol of CaCl2=40, 078g + 2x (35, 453g )= 110, 98g
110, 98 g ---1 mol
25 g---X= (25g x1 mol)/110, 98g= 0,23mol
250g solvent -----0,23 mol CaCl2 (the solute)
1000g solvent ----X = (1000g x0,23mol)/250g =0,90 mol solute
The solution is 0,90 molal
Answer:
I'm pretty sure the answers for this is D, C, and B.
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