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3 years ago

I am flooding these ( T_T)

Mathematics

1 answer:

dimulka [17.4K]3 years ago

7 0

That should be 5 2/3 qt.

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Find the area of the following<br> kite:<br> A = [?] m²<br> 40 m<br> 16 m<br> 16 m<br> 6 m

Rama09 [41]

Answer:

$Area_{kite}=736m^2$

Step-by-step explanation:

There are a few methods to find the area of this figure:

1. kite area formula

2. 2 triangles (one top, one bottom)

3. 2 triangles (one left, one right)

4. 4 separate right triangles.

<h3><u>Option 1: The kite area formula</u></h3>

Recall the formula for area of a kite: $Area_{kite}=\frac{1}{2} d_{1}d_{2}$ where d1 and d2 are the lengths of the diagonals of the kite ("diagonals" are segments that connect non-adjacent vertices -- in a quadrilateral, vertices that are across from each other).

If you've forgotten why that is the formula for the area of a kite, observe the attached diagram: note that the kite (shaded in) is half of the area of the rectangle that surrounds the kite (visualize the 4 smaller rectangles, and observe that the shaded portion is half of each, and thus the area of the kite is half the area of the large rectangle).

The area of a rectangle is $Area_{rectangle}=bh$ , sometimes written as $Area_{rectangle}=bh$ , where w is the width, and h is the height of the rectangle.

In the diagram, notice that the width and height are each just the diagonals of the kite. So, the <u>Area of the kite</u> is <u>half of the area of that surrounding rectangle</u> ... the rectangle with sides the lengths of the kite's diagonals.Hence, $Area_{kite}=\frac{1}{2} d_{1}d_{2}$

For our situation, each of the diagonals is already broken up into two parts from the intersection of the diagonals. To find the full length of the diagonal, add each part together:

For the horizontal diagonal (which I'll call d1): $d_{1}=40m+6m=46m$

For the vertical diagonal (which I'll call d2): $d_{2}=16m+16m=32m$

Substituting back into the formula for the area of a kite:

$Area_{kite}=\frac{1}{2} d_{1}d_{2}\\Area_{kite}=\frac{1}{2} (46m)(32m)\\Area_{kite}=736m^2$

<h3><u /></h3><h3><u>Option 2: The sum of the parts (version 1)</u></h3>

If one doesn't remember the formula for the area of a kite, and can't remember how to build it, the given shape could be visualized as 2 separate triangles, the given shape could be visualized as 2 separate triangles (one on top; one on bottom).

Visualizing it in this way produces two congruent triangles. Since the upper and lower triangles are congruent, they have the same area, and thus the area of the kite is double the area of the upper triangle.

Recall the formula for area of a triangle: $Area_{triangle}=\frac{1}{2} bh$ where b is the base of a triangle, and h is the height of the triangle <em>(length of a perpendicular line segment between a point on the line containing the base, and the non-colinear vertex)</em>. Since all kites have diagonals that are perpendicular to each other (as already indicated in the diagram), the height is already given (16m).

The base of the upper triangle, is the sum of the two segments that compose it: $b=40m+6m=46m$

<u>Finding the Area of the upper triangle</u> $Area_{\text{upper }triangle}=\frac{1}{2} (46m)(16m) = 368m^2$

<u>Finding the Area of the kite</u>

$Area_{kite}=2*(368m^2)$

$Area_{kite}=736m^2$

<h3><u>Option 3: The sum of the parts (version 2)</u></h3>

The given shape could be visualized as 2 separate triangles (one on the left; one on the right). Each triangle has its own area, and the sum of both triangle areas is the area of the kite.

<em>Note: In this visualization, the two triangles are not congruent, so it is not possible to double one of their areas to find the area of the kite.</em>

The base of the left triangle is the vertical line segment the is the vertical diagonal of the kite. We'll need to add together the two segments that compose it: $b=16m+16m=32m$ . This is also the base of the triangle on the right.

<u>Finding the Area of left and right triangles</u>

$Area_{\text{left }triangle}=\frac{1}{2} (32m)(40m) = 640m^2$

The base of the right triangle is the same length as the left triangle: $Area_{\text{right }triangle}=\frac{1}{2} (32m)(6m) = 96m^2$

<u>Finding the Area of the kite</u>

$Area_{kite}=(640m^2)+(96m^2)$

$Area_{kite}=736m^2$

<h3><u>Option 4: The sum of the parts (version 3)</u></h3>

If you don't happen to see those composite triangles from option 2 or 3 when you're working this out on a particular problem, the given shape could be visualized as 4 separate right triangles, and we're still given enough information in this problem to solve it this way.

<u>Calculating the area of the 4 right triangles</u>

$Area_{\text{upper left }triangle}=\frac{1}{2} (40m)(16m) = 320m^2$

$Area_{\text{upper right }triangle}=\frac{1}{2} (6m)(16m) = 48m^2$

$Area_{\text{lower left }triangle}=\frac{1}{2} (40m)(16m) = 320m^2$

$Area_{\text{lower right }triangle}=\frac{1}{2} (6m)(16m) = 48m^2$

<u>Calculating the area of the kite</u>

$Area_{kite}=(320m^2)+(48m^2)+(320m^2)+(48m^2)$

$Area_{kite}=736m^2$

8 0

2 years ago

The function A = A 0 e -0.0077x models the amount in pounds of a particular radioactive material stored in a concrete vault, whe

AysviL [449]

Answer:

After 80 years 432 pounds of radioactive element will be remaining.

Step-by-step explanation:

A function $A_{t}=A_{0}e^{-0.0077x}$ models the amount of a radioactive material.

Here x = number of years taken for decay.

If $A_{t}=432$ pound and $A_{0}=800$ pound, then we have to calculate the time for decay.

$A_{t}=A_{0}e^{-0.0077x}$

$432=800e^{-0.0077x}$

$e^{-0.0077x}=\frac{432}{800}$

Take log on both the sides of the equation

$ln(e^{-0.0077x})=ln(\frac{432}{800} )$

-0.0077x = ln(0.54)

-0.0077x = -0.616186

x = $\frac{0.616186}{0.0077}$

x = 80.02 years

Therefore, After 80 years 432 pounds of radioactive element will be remaining.

6 0

3 years ago

Can someone pls explain how this is the answer pls...

bija089 [108]

Answer:

5.325 gallons or $5 \frac{13}{40}$

Step-by-step explanation:

According to the given problem, Dr. Silva's tank holds up to 16 7/8 gallons = 16.875.

Transform 7/8 into decimal: Divide the numerator by the denominator = 0.875. Add that to 16, and you'll have the full tank capacity of 16.875.

Next, the prompt states that she filled 11.55 gallons' worth of gas. To find how much her tank had before she filled it, you could simply subtract the full tank capacity and the amount of gass added into the tank.

16.875 - 11.55 = 5.325 gallons or $5 \frac{13}{40}$ (13/40 is the same as 0.325).

5 0

3 years ago

SOLVE each system by graphing PLEASSE

dexar [7]

Answer:

Step-by-step explanation:

The given equations are:

$y=-\frac{1}{3}x+3$ and $y=2x-4$

On solving $y=-\frac{1}{3}x+3$ , we get the graph which is red in colour.

By Putting x=o in the equation⇒y=3

Putting x=-3⇒y=4

Now, plotting the graph for the equation $y=2x-4$ , it is plotted as blue colour by putting x=0⇒y=-4 and by putting x=3⇒y=2, Following the same path, we can plot the two graphs for the given equations.

8 0

3 years ago

Mr. Nguyen bought a package of 4 chicken legs and a package of 6 chicken wings. Ms. Dawen bought a package of 3 chicken legs and

gulaghasi [49]

Answer:

weight of legs - 7 ounces

weight of wings - 4 ounces

Step-by-step explanation:

Let the weight of a chicken leg be represented by l

Let the weight of a chicken wing be represented by w

The total weight of Mr. Nguyen's package can be represented by this equation :

4l + 6w = 52

The total weight of Ms. Dawen's package can be represented by this equation :

3l + 6w = 45

To find the weight of the legs and wing, use simultaneous equation

4l + 6w = 52 eqn 1

3l + 6w = 45 eqn 2

Subtract equation 2 from 1

l = 7 ounces

Substitute for l in equation 1

4(7) + 6w = 52

28 + 6w = 52

Solve for w

w = 4 ounces

4 0

3 years ago