Answer:
C. The 6th term is positive/negative 80
Step-by-step explanation:
Given
Geometric Progression


Required

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;
To solve the common ratio;
Divide the 7th term by the 5th term; This gives

Divide the numerator and the denominator of the fraction by 40
----- equation 1
Recall that the formula of a GP is

Where n is the nth term
So,


Substitute the above expression in equation 1
becomes


Square root both sides

r = ±
Next, is to solve for the first term;
Using 
By substituting 160 for T5 and ±
for r;
We get


Multiply through by 16



Now, we can easily solve for the 6th term
Recall that the formula of a GP is

Here, n = 6;



r = ±
So,
or 
or 
or 
±80
Hence, the 6th term is positive/negative 80
Do you know how to draw a bar graph?
Or model.
It's not something I can draw on this. But for purposes of helping you find how many feet deeper the Marina to the Puerto Rico trench
36,201 minus 27,493
Hope it helps! If it is, Brainliest please!
Answer:
Step-by-step explanation:
Remark
f(x) = 9x^2 - 5x + 3 is given. The notation means that wherever you see and x on the right, you replace it with the x in the brackes on the left. f(3) is a direction, not anything you have to adjust or manipulate.
Solution
f(-3) = 9*(-3^2) - 5*(-3) + 3 (-(3))^2 = -3 * -3 = 9 two minuses make a +
f(-3) = 9*(-3)(-3) + 15 + 3 -3 times an operation of minus equals a +
f(-3) = 9 * 9 + 15 + 3
f(-3) = 81 + 15 + 3
Answer: f(-3) = 99