Let's buils the intersection plane:
Point P is on AB and AP=2, then PB=3; point Q is on AE and AQ=1, then QE=4. Let P' be a point on CD such that CP'=2 and Q' be a point on the plane CDHG such that P'Q'=1 and P'Q' is perpendicular to CD. The line CQ' intersects HD at point R and the plane CPQR is intersection plane.
Consider triangles ΔCDR and ΔCP'Q', they are similar. So,
,
so R is a midlepoint of the side HD (for details see picture).
The answer is D: to dilate the triangle by a scale factor of 1:2 (or 1/2).
I hope this Helps!
D the identity property of addition. Adding zero to any number does not change the number