Median is the middle number in a set of numbers. If we have two middle numbers, we get the average. And from the question, listing them out, we have this
y=a(x-h)^2+k vertex is (h,k) we know that vertex is (4,0) input that point for (h,k) y=a(x-4)^2+0 y=a(x-4)^2 passes thorugh the point (6,1) input that point to find a 1=a(6-4)^2 1=a(2)^2 1=a(4) divide both sides by 4 1/4=a
thefor the equation is y=(1/4)(x-4)^2 or y=(1/4)x^2-2x+4
