All categories

3 years ago

What is the median of those in the the picture please help

Mathematics

1 answer:

Molodets [167]3 years ago

5 0

Answer:

Median is 24.5

Step-by-step explanation:

Median is the middle number in a set of numbers. If we have two middle numbers, we get the average. And from the question, listing them out, we have this

0,1, 2, 3,4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49.

The middle number here is 24 and 25. Getting their average will be 24.5

You might be interested in

1. Make up two equations, one that is true and one that is false. Do not state which equation is true and which is false. Your c

N76 [4]

1. The equations that I can think of are,
3 + 1 = 11 - 6
and
8 - 1 = 6 + 1

2. An example of equation that uses the variable x,
6x - 2x = 8
It may be required of you to perform certain steps in order to determine the value of x.

6 0

2 years ago

Read 2 more answers

A square with an area of 64 in2 is rotated to form a cylinder. What is the radius of the cylinder?

romanna [79]

The area of the square is calculated through the equation,

Area = e²

where e is the measure of sides.

From the given,

64 = e²
e = sqrt 64 = 8 inches

The length of the side of the square rotated to form the cylinder is the diameter of the base of the cylinder. To get the radius, we divide the diameter by 2.

radius = 8 inches / 2 = 4 inches

Thus, the radius of the cylinder is equal to 4 inches.

5 0

3 years ago

Can someone please help me with this question?!? I am so confused and I don't know how to answer it.

lbvjy [14]

9514 1404 393

Answer:

a. f(0) = 1

b. DNE (does not exist)

c. DNE

d. lim = 3

Step-by-step explanation:

The function exists at a point if it is defined there. The function is defined anywhere on the solid line and at solid dots. It is not defined at open circles. So, the function is defined everywhere except (2, 3), which has an open circle.

The open circle at (0, 4) prevents the function from being doubly-defined at x=0, since it is already defined to be 1 at x=0.

This discussion tells you ...

f(0) = 1

f(2) does not exist. There is a "hole" in the function definition there.

The function has a limit at a point if approaching from the left and approaching from the right have you approaching that same point.

Consider the point (1, 2). The graph is a solid line through that point. Approaching from values less than x=1, we get to the same point (1, 2) as when we approach from values greater than x=1.

Similarly, consider the point (2, 3). Approaching from values of x less than 2, we get to the same point (2, 3) as when we approach from x-values greater than 2. The limit at x=2 is 3. The only difference from the previous case is that the function is not actually defined to be that value there.

Now consider what happens at x=0. When we approach from the left, we approach the point (0, 4). When we approach from the right, we approach the point (0, 1). These are different points. Because they are different coming from the left and from the right, we say "the limit as x→0 does not exist."

In summary, ...

a) f(0) = 1

b) lim x → 0 does not exist

c) f(2) does not exist

d) lim x → 2 = 3

_____

Additional comment

The significance of the function not being defined at a point where the limit exists, (2, 3), is that the function is not continuous there. This kind of discontinuity is called "removable", because we could make the function continuous at x=2 by defining f(2) = 3 (that is, "filling the hole").

6 0

2 years ago

Help meeeee pleaseeeee:(

Marat540 [252]

Answer:

1 to 100m..............

7 0

2 years ago

Order from least to greatest 0.5 0.41 3/5

FinnZ [79.3K]

Least. 0.41, 0.5, 3/5 Greatest

4 0

3 years ago

Read 2 more answers