Ask question

Ask question

All categories

3 years ago

12

If you dunked a basketball and hung on to the rim, what force or forces would be acting on you while you were hanging on the rim

?
a. tension and gravitational forces
b. tension force only
c. gravitational force only

2 answers:

Paha777 [63]3 years ago

7 0

A tension and gravitational forces

BabaBlast [244]3 years ago

5 0

Selection A is appropriate.

_____
The rim is exerting an upward force on your fingers (creating tension in your fingers and arms); gravity is exerting a downward force on your body's center of mass.

You might be interested in

What is the value of the underlined digit? 625

VLD [36.1K]

The value of 6 would be 600 the value of 2 is 20 and. 5 is 5.

3 0

2 years ago

Eduardo spent $34 on a magazine and some candy bars if the magazine cost $6 and each candy bar cost $4 then how many candy bars

tatiyna

Answer: 7 candy bars

Step-by-step explanation:

First we need to subtract the cost of the magazine from the total cost

$34-$6=$28

Now the $28 that remains is the cost of all the candy bars, so if we divide by the price, we will get the amount.

$28/$4=7 candy bars

7 0

3 years ago

An electronics company produces transistors, resistors, and computer chips. Each transistor requires 3 units of copper, 1 unit

padilas [110]

Answer:

An electronics company can be produce 350 transistors and 340 computer chips, they can´t produce resistors.

Step-by-step explanation:

1. We will name the variables for transistors, resistors and the computer chips.

a = Transistors

b= Resistors

c = Computer chips

2. We propose three linear equations, one for the copper, one for the zinc and one for the glass.

$\left \{ {{3a+3b+2c=1730} \atop {a+2b+c=690}}\atop {2a+b+2c=1380}} \right.$

3. We write the matrix form as Ax=d

$A=\left(\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right)$

$x=\left(\begin{array}{ccc}a\\b\\c\end{array}\right)$

$A=\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)$

With this formula the solution of x is $x=\frac{d}{A}$ or $x=A^{-1}d$

4. We will find the inverse matrix $A^{-1}$ using the formula:

$A^{-1} = \frac{1}{detA} (C_{A})^{T}$

a. det A

$det A=\left[\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right] =3*(4-1)-3*(2-2)+2*(1-4)=9-0-6=3$

b. $(C_{A})^{T}$

$C_{A}=\left(\begin{array}{ccc}4-1&.(2-2)&1-4\\-(6-2)&6-4&-(3-6)\\3-4&-(3-2)&6-3\end{array}\right)$

$C_{A}=\left(\begin{array}{ccc}3&.0&-3\\-4&2&3\\-1&-1&3\end{array}\right)$

$(C_{A}) ^T=\left(\begin{array}{ccc}3&0&-3\\-4&2&3\\-1&-1&3\end{array}\right)^T$

$(C_{A}) ^T=\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)$

c. $A^{-1}$

$A^{-1}=\frac{1}{3} \left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)$

5. As $x=\frac{d}{A}$ or $x=A^{-1}d$ , the solution of x is:

$x=\frac{1}{3}\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)$

$x=\frac{1}{3}\left(\begin{array}{ccc}(3*1730)+(-4*690)+(-1*1380)\\(0*1730)+(2*690)+(-1*1380)\\(-3*1730)+(3*690)+(3*1380)\end{array}\right)$

$x=\frac{1}{3}\left(\begin{array}{ccc}1050\\0\\1020)\end{array}\right)$

$X=\left[\begin{array}{ccc}350\\0\\340\end{array}\right]$

<u><em>Therefore:</em></u>

<u><em>a= 350 Transistors</em></u>

<u><em>b=0 Resistors</em></u>

<u><em>c=340 Computer chips</em></u>

4 0

2 years ago

Can someone please help me with this question ?

____ [38]

The cost of water would be $615 as he needs 3 acre-feet of water for 205 acre/ft

5 0

2 years ago

What is the tangent ratio for ∠A?

Mashcka [7]

Answer:

1/2

Step-by-step explanation:

5 0

3 years ago