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3 years ago

Which object is an insulator?

Physics

2 answers:

Jobisdone [24]3 years ago

8 0

Answer:

Wood, plastic, rubber, etc.

Explanation:

There are two types of objects.

1. Conductors

2. Insulators

Conductors are the material through which electricity can pass easily.

For example, iron, copper, silver, gold, aluminium, etc.

Insulators are the material through which electricity cannot pass.

For example, rubber, plastic, wood, etc.

Helga [31]3 years ago

5 0

An insulator is an object that prevents the flow of electricity. Examples of such are rubber, plastic, wood, ceramic.

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Terminal velocity. A rider on a bike with the combined mass of 100kg attains a terminal speed of 15m/s on a 12% slope. Assuming

Firlakuza [10]

Answer:

0.9378

Explanation:

Weight (W) of the rider = 100 kg;

since 1 kg = 9.8067 N

100 kg will be = 980.67 N

W = 980.67 N

At the slope of 12%, the angle θ is calculated as:

$tan \ \theta = \dfrac{12}{100} \\ \\ tan \ \theta = 0.12 \\ \\ \theta = tan^{-1}(0.12) \\\\ \theta = 6.84^0$

The drag force D = Wsinθ

$\dfrac{1}{2}C_v \rho AV^2 = W sin \theta$

where;

$\rho = 1.23 \ kg/m^3$

A = 0.9 m²

V = 15 m/s

∴

Drag coefficient $C_D = \dfrac{2 *W*sin \theta}{\rho *A *V^2}$

$C_D =\dfrac{2 *980.67*sin 6.84}{1.23 *0.9 *15^2}$

$C_D =0.9378$

8 0

3 years ago

Sally Sizzle builds a circuit by connecting three resistors in oarallel with a 9v battery. The current in this curvuit is 3.6 am

Sergeeva-Olga [200]

Answer:

The new resistor has resistance of 9Ω.

Explanation:

The effective resistance of three resistance is

$(1). \: \: \frac{1}{R_e} = \frac{1}{R_1}+ \frac{1}{R_2}+ \frac{1}{R_3}$ .

we know the the circuit with 9V battery has current of 3.6A; therefore, $R_e$ must be

$V = IR_e$

$R_e = \dfrac{V}{I} = \dfrac{9V}{3.6A}$

$R_e = 2.5\Omega$ ,

which means

$\frac{1}{2.5\Omega } = \frac{1}{R_1}+ \frac{1}{R_2}+ \frac{1}{R_3}$

$\boxed{0.4\Omega^{-1} = \frac{1}{R_1}+ \frac{1}{R_2}+ \frac{1}{R_3} .}$

Now, Sally wants to connect another resistor in parallel so that the current becomes 4.6A. The resistance required for that is

$R_{new} = \dfrac{9V}{4.6A}$

$R_{new} = 1.957 \Omega$ .

which means the 4th resistor $R_4$ must satisfy the equation

$(2), \: \: \frac{1}{1.957\Omega} = \frac{1}{R_1}+ \frac{1}{R_2}+ \frac{1}{R_3}+\frac{1}{R_4} ,$

and since

$\frac{1}{R_1}+ \frac{1}{R_2}+ \frac{1}{R_3} =0.4\Omega^{-1},$

equation (2) becomes

$\frac{1}{1.957\Omega} =0.4\Omega^{-1}+\frac{1}{R_4} ,$

which we solve for $R_4$ :

$0.511\Omega^{-1} =0.4\Omega^{-1}+\frac{1}{R_4} ,$

$0.111\Omega^{-1} = \dfrac{1}{R_4}$

$\boxed{R_4 = 9\Omega}$

Thus, the resistance of the new resistor is 9 ohms.

3 0

4 years ago

An object at free fall near the Earth’s surface experiences constant velocity.

mariarad [96]

False it accelerates.

7 0

4 years ago

A 69-kg student sitting on a hardwood floor does not slide until pulled by a 260-N horizontal force. find coefficient of frictio

salantis [7]

Answer:

μ = 0.385

Explanation:

Given that,

The mass of the student, m = 69 Kg

The horizontal force applied, F = 260 N

The normal force acting on the body, weight = mg = 69g N

= 676.2 N

The coefficient of friction acting on a body is equal to the force acting on the body to the normal force acting on the body due to gravitation.

The formula for coefficient of friction,

μ = F / N

Substituting the values in the above equation,

μ = 260 N / 676.2 N

= 0.385

Hence, the coefficient of friction, μ = 0.385

6 0

3 years ago

A straight wire segment 5 m long makes an angle of 30° with a uniform magnetic field of 0.37 T. Find the magnitude of the force

SIZIF [17.4K]

Answer:

The magnitude of the force on the wire is 2.68 N.

Explanation:

Given that,

Length of the wire, L = 5 m

Magnetic field, B = 0.37 T

Angle between wire and the magnetic field, $\theta=30^{\circ}$

Current in the wire, I = 2.9 A

We need to find the magnitude of the force on the wire. The magnetic force in the wire is given by :

$F=BIL\ \sin\theta\\\\F=0.37\ T\times 2.9\ A\times 5\ m\times \ \sin(30)\\\\F=2.68\ N$

So, the magnitude of the force on the wire is 2.68 N. Hence, this is the required solution.

7 0

3 years ago