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Pavlova-9 [17]
3 years ago
12

A straight wire segment 5 m long makes an angle of 30° with a uniform magnetic field of 0.37 T. Find the magnitude of the force

on the wire if it carries a current of 2.9 A.
Physics
1 answer:
SIZIF [17.4K]3 years ago
7 0

Answer:

The magnitude of the force on the wire is 2.68 N.

Explanation:

Given that,

Length of the wire, L = 5 m

Magnetic field, B = 0.37 T

Angle between wire and the magnetic field, \theta=30^{\circ}

Current in the wire, I = 2.9 A

We need to find the magnitude of the force on the wire. The magnetic force in the wire is given by :

F=BIL\ \sin\theta\\\\F=0.37\ T\times 2.9\ A\times 5\ m\times \ \sin(30)\\\\F=2.68\ N

So, the magnitude of the force on the wire is 2.68 N. Hence, this is the required solution.

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When the frequency of an ac circuit is decreased, the current in the circuit increases. which combination of elements is most li
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Answer:

The combination of elements most likely to comprise the circuit are resistor, inductor and capacitor

Explanation:

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2 years ago
Use Newton’s Universal Law of Gravitation to calculate the magnitude of the gravitational force between a 200 kg refrigerator an
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Answer:

3.735×10⁻⁶ N

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From newton' s law of universal gravitation,

F = Gmm'/r² .............................. Equation 1

Where F = Gravitational force between the person and the refrigerator, m = mass of the person, m' = mass of the refrigerator, r = distance between the person and the refrigerator. G = gravitational universal constant.

Given: m = 70 kg, m' = 200 kg, r = 0.5 m

Constant: G = 6.67×10⁻¹¹ Nm²/kg².

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F = 93380×10⁻¹¹/0.25

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F = 3.735×10⁻⁶ N

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41kg object that is moving east at 5 m s

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