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Alecsey [184]
3 years ago
9

One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a

space station that spins about its center at a constant rate. This creates "artificial gravity" at the outside rim of the station. ?
Physics
1 answer:
Maurinko [17]3 years ago
6 0

This question is not complete.

The complete question is as follows:

One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a space station that spins about its center at a constant rate. This creates “artificial gravity” at the outside rim of the station. (a) If the diameter of the space station is 800 m, how many revolutions per minute are needed for the “artificial gravity” acceleration to be 9.80m/s2?

Explanation:

a. Using the expression;

T = 2π√R/g

where R = radius of the space = diameter/2

R = 800/2 = 400m

g= acceleration due to gravity = 9.8m/s^2

1/T = number of revolutions per second

T = 2π√R/g

T = 2 x 3.14 x √400/9.8

T = 6.28 x 6.39 = 40.13

1/T = 1/40.13 = 0.025 x 60 = 1.5 revolution/minute

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3 years ago
Kepler proposed the modern model of the solar system. <br> True or False
givi [52]

Answer:

True

Explanation:

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4 0
3 years ago
A large spool in an electrician's workshop has 55 m of insulation coated wire coiled around it. when the electrician connects a
goblinko [34]

Answer:

21.2 m

Explanation:

The current in the wire is given by Ohm's law:

I=\frac{V}{R}

where V is the voltage of the battery and R is the resistance of the wire.

The resistance of the wire is directly proportional to the length of the wire, so we can write:

R=kL

where k is a constant and L is the length of the wire. Substituting into the first equation,

I=\frac{V}{kL}

We can rewrite this equation also as

\frac{V}{k}=IL

where the term on the left is a constant (because the voltage of the battery does not change). So, we can write:

I_1 L_1 = I_2 L_2

where:

I_1 = 1.0 A is the current in the first situation

L_1 = 55 m is the length of the wire in the first situation

I_2 = 2.6 A is the current in the second situation

L_2=? is the length of the wire in the second situation

Re-arranging the formula, we can find the value of L2:

L_2 = \frac{I_1 L_1}{I_2}=\frac{(1.0 A)(55 m)}{2.6 m}=21.2m

8 0
3 years ago
The capacitance of a Pt-n-type GaAs Schottky diode is given by 1 (C(μF))2 = 1.0 × 105 − 2.0 × 105 V The diode area is 0.1 cm2. C
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Answer:

built in potential Vbi = +0.5V

barrier height = 0.139 V

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Explanation:

5 0
3 years ago
A wave has a frequency of 450 Hz and a wave length of 00.52 m what is the speed of the wave?
nata0808 [166]
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4 0
3 years ago
Read 2 more answers
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