Water evaporates at 100⁰C
So change in temperature = 100-20 = 80⁰C
Amount of water to be evaporated = 1 liter = 1L*1kg/liter = 1 kg
Specific heat of water is 1 calorie/gram ⁰C = 4.186 joule/gram =4186 J/kg
So heat required E = mcΔT = 1 * 4186 *80= 334880 J =334.88 kJ
So amount of heat require to evaporate water = 334.88 kJ
The answer is struggling to perform
Answer:
new energy of the capacitor is half that of initial energy
Explanation:
As we know that the energy stored in the capacitor is given as

here we know that capacitance of parallel plate capacitor is given as

V = voltage of battery
so now we have capacitor remains connected to the same battery and the separation between the plates is doubled
so we have

so now the energy stored between the plates is

so new energy of the capacitor is half
It is often necessary to convert one metric measurement to another unit—this happens frequently in the medical, scientific, and technical fields, where the metric system is commonly used.