Answer:
lw +
× π ×
⇒ Answer D is correct
Step-by-step explanation:
First, let us find the area of the semi-circle.
Area =
× π × r²
<u>Given that,</u>
diameter of the semi-circle is ⇒ <em>l</em>
∴ radius ⇒ <em>l / 2</em>
<u>Let us find it now.</u>
Area =
× π × r²
Area =
× π × 
<u> </u>
Secondly, let us find the area of the rectangle.
Area = length × width
<u>Given that,</u>
length ⇒ <em>l</em>
width ⇒ w
<u>Let us find it now.</u>
Area = length × width
Area = l ×w
Area = lw
<u> </u>
And now let us <u>find the total area.</u>
Total area = Area of the rectangle + Area of the semi - circle
Tota area = lw +
× π × 
For this case, the first thing we want to do is substitute the value of y = 15 in the equation.
We have then:
15 = -0.08x ^ 2 + 1.6x + 10
Rewriting we have:
0 = -0.08x ^ 2 + 1.6x + 10 - 15
0 = -0.08x ^ 2 + 1.6x - 5
The solutions are:
x1 = 3.876275643042054
x2 = 16.123724356957947
Nearest whole number:
x1 = 4
x2 = 16
were about 15 tons of trout caught in the lake in the years:
1995 + 4 = 1999
1995 + 16 = 2011
Answer:
The year 1999 and the year 2011
The given sequence is:

a(2)=1
a(3)=3
a(4)=9
We are to find the average rate of change between n=3 and n=4 for the given function.
Average rate of change =

So the average rate of change for the given function from n = 3 to n = 4 is 6
Reflexive property of Equality is your answer!
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Step-by-step explanation:
use the identity a²-b²=(a-b)(a+b)
x²-4=(x-2)(x+2)
so the answer is x-2