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3 years ago

Help me on all please

Mathematics

1 answer:

nirvana33 [79]3 years ago

4 0

Answer:

look at the rest

Step-by-step explanation:

1.)same line

2.)intersect

3.)parallel

4.)ordered pair

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A data set consists of the following data points:

aleksley [76]

<span>(3,5),
(5,8),
(6,13)
------
(14,26)/3

then use the point slope form of a line to find equation of line

</span> $y-y_1=m(x-x_1)
\\y - \frac{26}{3} = 2.5(x- \frac{14}{3})
\\y - \frac{26}{3} = \frac{5}{2} (x- \frac{14}{3})
\\y - \frac{26}{3} = \frac{5}{2} x- \frac{5}{2}\times\frac{14}{3}
\\y - \frac{26}{3} = \frac{5}{2} x- \frac{35}{3}
\\6y-52=15x-70
\\15x-6y-18=0$
<span>
Find y-intercept for x = 0.

</span> $15x-6y-18=0
\\15\times0-6y-18=0
\\-6y=18
\\y=-3$ <span>

</span>

4 0

3 years ago

HELP DUE IN AN HOUR WILL GIVE BRAINLIST!!!!!!!!

Marrrta [24]

Answer:

For the first one it is y=-3x-2

Step-by-step explanation:

7 0

3 years ago

Interior and Exterior Angle polygons. I need help to find the measure of a regular decagon. To find each interior angle and to f

Nadusha1986 [10]

<h3>Answer:</h3>

interior: 144°
exterior: 36°

<h3>Step-by-step explanation:</h3>

It may be easiest to remember that the sum of exterior angles of any convex polygon is always 360°.

Your decagon has a sum of exterior angles that is 360°. Since it is a regular 10-sided polygon, each one is 1/10 that value: 36°.

The measure of each exterior angle is 36°.

The measure of an interior angle is the supplement of the exterior angle. Each interior angle of the regular 10-sided polygon will be ...

... 180° -36° = 144°

The measure of each interior angle is 144°.

_____

A formula often used for the sum of the measures of the interior angles is ...

... interior angle total = (n -2)×180°

For a 10-sided figure, the interior angle total is ...

... (10 -2)×180° = 1440°

When this sum is divided into 10 equal angles, the measure of one interior angle is ...

... 1440°/10 = 144° . . . . . agrees with the above computation

The exterior angle measure is the supplement of this:

... 180° -144° = 36° . . . . . exterior angle measure; agrees with the above computation

5 0

3 years ago

Match each differential equation to a function which is a solution.

inessss [21]

Answer: 1 - C

2 - E

3 - no answer

4 - B

Step-by-step explanation:

A. $y = 3x+x^2$

$y' = 3 + 2x\\y'' = 2$

Replace in 1:

$y'' + y = 0$

$2 + 3x + x^2 \neq 0$

So, A is not an answer for 1

Replace in 2:

$y' = 3y$

$3+2x = 3(3x + x^2)$

So, A is not an answer for 2

Replace in 3

$2x^2y'' + 3xy'= y$

$2x^2(2) + 3x(3 + 2x) = 4x^2 + 9x + 6x^2 \neq 3x+x^2$

So, A is not an answer for 3

Replace in 4

$y'' + 6y' + 8y = 0$

$2 + 6(3+2x)+8(3x + x^2) = 2+18+12x+24x+8x^2 \neq 0$

So, A is not an answer for 4

B. $y = e^{-4x}$

$y' = -4e^{-4x}$

$y'' = 16e^{-4x}$

Replace in 1

$y'' + y = 0$

$16e^{-4x} -4e^{-4x} = 12e^{-4x} \neq 0$

So, B is not an answer for 1

Replace in 2

$y' = 3y$

$-4e^{-4x} \neq 3e^{-4x}$

So, B is not an answer for 2

Replace in 3

$2x^2y'' + 3xy' = y$

$2x^2(16e^{-4x}) +3x(-4e^{-4x}) \neq e^{-4x}$

So, B is not an answer for 3

Replace in 4

$y'' + 6y' +8y = 0$

$16e^{-4x} + 6(-4e^{-4x}) + 8e^{-4x} = e^{-4x}(16-24+8) = 0$

So, B is an answer for 4

C. $y = sin(x)$

$y' = cos(x)$

$y'' = -sin(x)$

Replace in 1

$y'' + y = 0$

$-sin(x) + sin(x) = 0$

So, C is an answer for 1

We jump to

D. $y = x^{12}$

$y' = 12x^{11}$

$y'' = 132 x^{10}$

Replace in 2

$y' = 3y$

$12x^{11} \neq 3x^{12}$

So, D is not an answer for 2

Replace in 3

$2x^2y'' + 3xy' = y$

$2x^2(132x^{10}) + 3x(12x^{11}) = 300x^{12} \neq x^{12}$

So, D is not an answer for 3

E. $y = 6e^{3x}$

$y' = 18e^{3x}$

$y'' = 54e^{3x}$

Replace in 2

$y' = 3y$

$18e^{3x} = 3(6e^{3x}) = 18e^{3x}$

So, E is an answer for 2

3 0

3 years ago

Help me with this plz

Dmitrij [34]

Answer:

the third one

Step-by-step explanation:

We can break it up into $(-8*3)*(x*x^2)$ . This means that it is $-24*x^3$ , or $-24x^3$

7 0

3 years ago