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4 years ago

3/5(x+2)=x-4What is the answer?Is it one solution,no solution, or Infinite solution?

Mathematics

1 answer:

Klio2033 [76]4 years ago

3 0

Answer:

One solution

Step-by-step explanation:

3/5(x+2)=x-4

I do not like working with fractions, so I will multiply by 5 on each side to clear the fractions.

5 *3/5(x+2)=5*(x-4)

3*(x+2)= 5*(x-4)

Distribute

3x+6 = 5x-20

Subtract 3x from each side

3x+6 = 5x-20

3x-3x+6 = 5x-3x-20

6 = 2x-20

Add 20 to each side

6+20 =2x-20+20

26 =2x

Divide each side by 2

26/2 = 2x/2

13=x

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3 years ago

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‐(5k – 3) ≤ 15 + 3k :) pls help

Juliette [100K]

Answer:

k≥-1.5

Step-by-step explanation:

-(5k-3) ≤ 15 + 3k

-5k+3 ≤15 +3k

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3 years ago

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Perform the indicated operations. x+1/3y+x-2/4y-x=3/6y

Varvara68 [4.7K]

The answer:
_____________________________________________
x = (⅔)y ;

y = 3x/2.
_____________________________________________
Given:

x + (⅓)y + x - (2/4)y - x = (3/6)y ;
______________________________________

Take the: x + x - x = 1x + 1x - 1x = 2x - 1x = 1x = x ;

and rewrite:

x + (⅓)y - (2/4)y = (3/6)y ;
_______________________________
Note that: (2/4)y = (½)y ;

and: (3/6)y = (½)y ; so;
___________________________
Rewrite as:
____________________________
x + (⅓)y - (½)y = (½)y ;

Add "(½)y" to EACH SIDE of the equation;
_________________________________
x + (⅓)y - (½)y + (½)y = (½)y + (½)y ;

to get: x + (⅓)y = y ;

x = 1y - (⅓)y = (3/3) y - (1/3)y - [ (3-1)/3] y = (⅔)y ;

So: x = (⅔)y ;

In terms of "y" ;

Given: (⅔)y = x ; Multiply each side of the equation by "3" ;

3*[(⅔)y] = 3*x ;

to get: 2y = 3x ;

Now, divide EACH SIDE of the equation by "2" ; to isolate "y" on one side of the equation; and to solve for "y" (in terms of "x"):

2y / 2 = 3x / 2 ;

to get:

y = 3x/2 ;
___________________________________

6 0

4 years ago

Please help me solve this problem ASAP

DiKsa [7]

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