All categories

3 years ago

As a fraction with variable(s), b over 4.9 = - 20.6 Solve for b

Mathematics

2 answers:

Pavlova-9 [17]3 years ago

8 0

Acc. to ques.
b/4.9 = -20.6
b = -20.6 × 4.9
b = -100.94

harkovskaia [24]3 years ago

7 0

Start with
b/4.9=-20.6

Multiply both sides by 4.9 you will be left with b

b=-20.6*4.9
b=-100.94

now to check

-100.94/4.9=-20.6

You might be interested in

Which of the following is the algebraic expression that best describes the sequence 3,6,9,12 ?

Novay_Z [31]

I don't see any choices so I am going to give you what I think the answer would be. The rule would be 3x. That would be you could plug any number in and they would give you the sequence. Example:
x = 1
x times 3 = 3.
We could even find future things like:
x = 10
x times 10 = 30.
If we were doing it based on the algebraic expression it would be "multiplication" because we are multiplying. Hope this helped. :)

6 0

3 years ago

Read 2 more answers

Which data value has the highest frequency? 116 316 38 58

lara31 [8.8K]

1/16. that is the value that has the most x's on the graph.

8 0

3 years ago

Read 2 more answers

A study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school

nekit [7.7K]

Answer:

We conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

Step-by-step explanation:

We are given that a study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school seniors in Illinois.

Results showed that 34 of the freshmen and 24 of the seniors had used anabolic steroids.

Let $p_1$ = proportion of Illinois high school freshmen who have used anabolic steroids.

$p_2$ = proportion of Illinois high school seniors who have used anabolic steroids.

SO, Null Hypothesis, $H_0$ : $p_1=p_2$ {means that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

Alternate Hypothesis, $H_A$ : $p_1\neq p_2$ {means that there is a significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of high school freshmen who have used anabolic steroids = $\frac{34}{1679}$ = 0.0203

$\hat p_2$ = sample proportion of high school seniors who have used anabolic steroids = $\frac{24}{1366}$ = 0.0176

$n_1$ = sample of high school freshmen = 1679

$n_2$ = sample of high school seniors = 1366

So, the test statistics = $\frac{(0.0203-0.0176)-(0)}{\sqrt{\frac{0.0203(1-0.0203)}{1679}+\frac{0.0176(1-0.0176)}{1366} } }$

= 0.545

The value of z test statistics is 0.545.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

3 0

2 years ago

Write equation to the line when m=2 and b=-1 Thanks!

vaieri [72.5K]

The equation of a line in slope intercept form is y=mx+b, which when you plug in the numbers becomes y=2x-1.

6 0

3 years ago

Could you please help me with questions 36 & 37?

Andrej [43]

We have to determine if the functions are linear or not.

We can do this by rearranging the equations in this form:

$y=mx+b$

where m and b are constants.

NOTE: There are many ways to prove that a function is linear, but this is the easiest for this question.

36.

$\begin{gathered} x+\frac{1}{y}=7 \\ \frac{1}{y}=-x+7 \end{gathered}$

As this function can not be written in the form y=mx+b, then it is not linear.

37.

$\begin{gathered} \frac{x}{2}=10+\frac{2y}{3} \\ \frac{x}{2}-10=\frac{2y}{3} \\ \frac{2y}{3}=\frac{1}{2}x-10 \\ y=\frac{3}{2}(\frac{1}{2}x-10) \\ y=\frac{3}{4}x-15 \end{gathered}$

This function is now in the form y=mx+b, where m=3/4 and b=-15. Then, this function is a linear function.

Answer:

36. Non-linear.

37. Linear.

8 0

1 year ago