Let A represent the value of the car after each year.
A= initial value (P)×(1+percent increase(r)) ^time
A=P×(1+r)^t
A=18710×(1+(-12%))^8
A=18710×(1-12%)^8
A=18710×(1-0.12)^8
A=18710×(0.88)^8
A= 6728.7619591115
The best approximation is 6729
Therefore the value of the car will be about $6729 after 8 years
Your answer is B.
Answer:
1
Step-by-step explanation:
Remember that anything to the 0th power is going to be 1 in terms of exponent rules!
Here’s a photo on how to do it! If you need help in more problems like this use a website called Symbolab!! It’s really helpful!!
This is all a bit complicated so try and stick with me on this one!
This one is the first problem in the first picture! a + 2 / a^2 + a - 1 / a + 1/ -a^2 - 2a - 1
= a^4 + a^3 - a^2 - a / -a^5 - 3a^4 - 3a^3 - a^2
= -a^3 - a^2 + a + 1 / a^4 + 3a^3 + 3a^2 + a
= -a^3 - a^2 + a + 1/ a^4 + 3a^3 + 3a^2 + a
= (-a - 1) (a + 1) (a - 1) / a(a+ 1) (a + 1) (a + 1)
= -a + 1 / a^2 + a
The second problem in the first picture! 3x / y + 3x - y^2 / 3xy - 9x^2 + y^2 + 9x^2 / y^2 - 9x^2
= -81x^4y + 18x^2y^3 - y^5 / 243x^5 - 54x^3y^2 + 3xy^4
This one is for the last picture! 4y^2 + 4y + 1 / 4y - 8y^2 - 4y^2 + 1 / 4y + y
= 16y^3 + 24y^2 / -32y^3 + 16u^2
= 16y + 24 / -32y + 16
= 2y + 3 / -4y + 2
I hope this was helpful!!!
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Answer:
x=136°
Step-by-step explanation:
x=136° ( as it's vertical angle to 136°)
