There are two <em>true</em> statements:
- When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
- V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.
<h3>How to use composition between two function</h3>
Let be <em>f</em> and <em>g</em> two functions, there is a composition of <em>f</em> with respect to <em>g</em> when the domain of <em>f</em> is equal to the range of <em>g</em>. In this question, the <em>domain</em> variable of the function V(r) is replaced by substitution.
If we know that V(r) = (4/3) · π · r³ and r(t) = (1/4) · t², then the composite function is:
V(t) = (4/3) · π · [(1/4) · t²]³
V(t) = (4/3) · π · (1/64) · t⁶
V(t) = (1/48) · π · t⁶
There are two <em>true</em> statements:
- When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
- V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.
To learn on composition between functions: brainly.com/question/12007574
#SPJ1
0.71 x 22 is the expression that works, because 1 AUD = 0.71USD.
Answer:
Step-by-step explanation:
If the Number of Sales of x units, N(x) is defined by the function:
Next, we text the critical points and the end points of the interval to see where the derivative is increasing.
Thus, the rate of change of sales 
is increasing in the interval on 10≤x≤40.
<u>Step-by-step explanation:</u>
To prove:
Identities used:
......(1)
........(2)
.......(3)
Taking the LHS:
Using identity 1:
Using identities 2 and 3:
As, LHS = RHS
Hence proved
