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algol13
3 years ago
15

Hi

Mathematics
1 answer:
klasskru [66]3 years ago
3 0

Answer:

Here is the solution,mate.

Hope it helps.

You might be interested in
What is 1 2/3 multiple 2/3
Flauer [41]

Answer:

1\frac{1}{9}

Step-by-step explanation:

Given the following question:

1\frac{2}{3} \times\frac{2}{3}

In order to multiply the two, we have to convert the mixed number into a improper fraction and then multiply the numerator by the numerator, the denominator by the denominator.

1\frac{2}{3} =3\times1=3+2=\frac{5}{3}
\frac{5}{3} \times\frac{2}{3}
5\times2=10
3\times3=9
=\frac{10}{9}

<u>Convert the improper fraction into a mixed number:</u>

\frac{10}{9}
\frac{10}{9} =10\div9=1\frac{1}{9}
=1\frac{1}{9}

Your answer is "1 1/9."

Hope this helps.

7 0
2 years ago
How many years is 694.44 days?
antoniya [11.8K]

Answer:

1.9 years

Step-by-step explanation:

There are 365 days in a year

694.44 / 365 = 1.9

Hope this helps!

6 0
2 years ago
Read 2 more answers
Find the length of the missing side
faltersainse [42]

Answer:

c = 17

Step-by-step explanation:

Since this is a right angle triangle we can use the Pythagoras theorem that states that c^{2} = a^{2} + b^{2} (where c is the Solve for  hypotenuse and "a" and "b" are the legs of the right angle triangle). From here we know that the answer to this question is....

c^{2} = a^{2} + b^{2}\\c^{2} = 15^{2} + 8^{2} \\c^{2} = 225 + 64\\c^{2} = 289\\c = \sqrt{289} \\c = 17

6 0
3 years ago
Problem 4: Let F = (2z + 2)k be the flow field. Answer the following to verify the divergence theorem: a) Use definition to find
Viktor [21]

Given that you mention the divergence theorem, and that part (b) is asking you to find the downward flux through the disk x^2+y^2\le3, I think it's same to assume that the hemisphere referred to in part (a) is the upper half of the sphere x^2+y^2+z^2=3.

a. Let C denote the hemispherical <u>c</u>ap z=\sqrt{3-x^2-y^2}, parameterized by

\vec r(u,v)=\sqrt3\cos u\sin v\,\vec\imath+\sqrt3\sin u\sin v\,\vec\jmath+\sqrt3\cos v\,\vec k

with 0\le u\le2\pi and 0\le v\le\frac\pi2. Take the normal vector to C to be

\vec r_v\times\vec r_u=3\cos u\sin^2v\,\vec\imath+3\sin u\sin^2v\,\vec\jmath+3\sin v\cos v\,\vec k

Then the upward flux of \vec F=(2z+2)\,\vec k through C is

\displaystyle\iint_C\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^{\pi/2}((2\sqrt3\cos v+2)\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm dv\,\mathrm du

\displaystyle=3\int_0^{2\pi}\int_0^{\pi/2}\sin2v(\sqrt3\cos v+1)\,\mathrm dv\,\mathrm du

=\boxed{2(3+2\sqrt3)\pi}

b. Let D be the disk that closes off the hemisphere C, parameterized by

\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath

with 0\le u\le\sqrt3 and 0\le v\le2\pi. Take the normal to D to be

\vec s_v\times\vec s_u=-u\,\vec k

Then the downward flux of \vec F through D is

\displaystyle\int_0^{2\pi}\int_0^{\sqrt3}(2\,\vec k)\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv=-2\int_0^{2\pi}\int_0^{\sqrt3}u\,\mathrm du\,\mathrm dv

=\boxed{-6\pi}

c. The net flux is then \boxed{4\sqrt3\pi}.

d. By the divergence theorem, the flux of \vec F across the closed hemisphere H with boundary C\cup D is equal to the integral of \mathrm{div}\vec F over its interior:

\displaystyle\iint_{C\cup D}\vec F\cdot\mathrm d\vec S=\iiint_H\mathrm{div}\vec F\,\mathrm dV

We have

\mathrm{div}\vec F=\dfrac{\partial(2z+2)}{\partial z}=2

so the volume integral is

2\displaystyle\iiint_H\mathrm dV

which is 2 times the volume of the hemisphere H, so that the net flux is \boxed{4\sqrt3\pi}. Just to confirm, we could compute the integral in spherical coordinates:

\displaystyle2\int_0^{\pi/2}\int_0^{2\pi}\int_0^{\sqrt3}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=4\sqrt3\pi

4 0
3 years ago
While sailing, Jacob is 150 feet from a lighthouse. The angle of elevation from his feet on the boat (at sea level) to the top o
Vlada [557]

Answer:

The height of the lighthouse is approximately 166.6 feet.

Step-by-step explanation:

Let the height of the lighthouse be represented by s, then;

Tan 48° = (opposite) ÷ (adjacent)

Tan 48° = s ÷ 150

⇒ s = 150 × Tan 48°

      = 150 × 1.1106

     = 166.59

s ≅ 166.6 feet

Therefore, the height of the lighthouse is approximately 166.6 feet.

7 0
3 years ago
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