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3 years ago

Which of the point-slope equations below are correct for the line that passes through points (-2, -2) and (2, 1)?

1 answer:

8 0

Find slope first:
m =y2-y1/x2-x1
m = 1--2/2--2
m = 3/4

Select a point, insert your slope, & put it into point slope form:
y-y1 =m(x-x1)

Your final answers are:

y-1=3/4(x-2)
OR
y+2 =3/4(x+2)

You might be interested in

Heather, Shen, and Aldo served a total of 57 orders Monday at the school cafeteria. Shen served 2 times as many as Aldo. Aldo se

pishuonlain [190]

Answer:

Shen served 32 orders, Aldo served 16 orders and Heather served 9 orders

Step-by-step explanation:

Let S represent Shen, A, Aldo and H, Heather

Now, let's interpret the question

Shen served 2 times as many as Aldo, this gives:

S = 2A ...eq 1

Aldo served 7 more orders than Heater

A = 7 + H ... eq 2

Slot in the value of A in eq 1

Therefore,

S = 2 (7 + H)

Expand the bracket

S = 14 + 2H

Shen, Heather and Aldo served a total of 57 orders

S + A + H = 57

Slot in the values of S and A

(14 + 2H) + (7 + H) + H = 57

14 + 2H + 7 + H + H = 57

Collect like terms

14 + 7 + 2H + H + H = 57

21 + 4H = 57

4H = 57 - 21

4H = 36

H = 9

Substitute the value of eq 2

A = 7 + H

A = 7 + 9

A = 16

Substitute the value of A in eq 1

S = 2A

S = 2(16)

S = 32

Therefore, Shen served 32 orders, Aldo served 16 orders and Heather served 9 orders

5 0

3 years ago

How many hours would it take to get 100k gold if i make 540 every ten minutes (and if possible teach me how to do this)

Veseljchak [2.6K]

Answer:

Round the 540 to 500 for ease, if you need 100k and have 500 every ten mins, just cross multiply the equation

Step-by-step explanation:

3 0

3 years ago

Please anyone answer me

ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

$A\frac{}{1} = ∫g(x)dx = ∫xdx = \frac{1}{2} {x}^{2} | \frac{2}{0} = 2$