Answer:
The area of a label is 
Step-by-step explanation:
we know that
The lateral area of a cylinder (label of the can) is equal to

we have that
A can is 4 inches wide
so
The diameter of the can is 4 inches
----> the radius is half the diameter
----> height of the label
substitute in the formula

Answer:
Hi I have to tell you But I also use Flvs Open lesson 01.07 and read it I promise you will find something of how to do it because I had the same prob and after reading the lesson and awnsering the quetion I GOT A 100 hope i help you
Step-by-step explanation:
Answer:
For the first one:
D) The perpendicular bisector of line MN
For the second one:
You need a protractor (angle ruler) to measure the angle. After finding the measurement, divide it into two. After finding the result, find the point that has that angle.
Example -
The pie measures 120°.
120° ÷ 2 = 60°
Find the point that measures 60° and connect the points (from the start to the edge of the pie).
For the third one:
C) m∠ABD ≅ m∠CBD
Answer:
5y = x + 11
Step-by-step explanation:
Given parameters:
Equation of the line ;
y = -5x + 1
Coordinates = (2, -1)
Find the equation of a line perpendicular;
Solution:
A line perpendicular to y = -5x + 1 will have slope that is a negative inverse of the given one.
Equation of a straight line is expressed as;
y = mx + c
y and x are the coordinates
m is the slope
c is the y-intercept
So, the slope of the new line perpendicular is
;
Now let us find the y-intercept of the new line;
x = -1 and y = 2
2 =
x (-1) + c
c = 2 +
=
The equation of the new line is;
y =
x +
or multiply through by 5;
5y = x + 11
Using the critical point concept, it is found that a = -3 and b = 7.
<h3>What are the critical points of a function?</h3>
- The critical points of a function are the values of x for which:

In this problem, the function is:

Hence, the derivative is:

Then:







Since the critical point is at x = 2, we have that:




Then:

Critical point at (2,3) means that when
, then:



You can learn more about the critical point concept at brainly.com/question/2256078