Factor 16b^2 - 40b +25
2 answers:
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Remember
the deritivive of f(x)/g(x)=(f'(x)g(x)-g'(x)f(x))/((g(x))^2)
deritivive of lnx is 1/x
derivitive of t^2=2t
so
=
=
the deritivive of f(x)/g(x)=(f'(x)g(x)-g'(x)f(x))/((g(x))^2)
deritivive of lnx is 1/x
derivitive of t^2=2t
so
Answer:
The graph of his initial step in the attached figure
Step-by-step explanation:
we have
This is a exponential function of the form
where
a is the initial value
b is the base
r is the rate of change
In this problem
a=3 ---> the initial value ( value of the function when the value of x is equal to zero)
b=4
b=1+r ----> 4=1+r ----> r=3 ---> r=300%
therefore
The initial value is the point (0,3)
The graph of his initial step in the attached figure
