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Varvara68 [4.7K]
3 years ago
12

The speed of cars on a stretch of road is normally distributed with an average 51 miles per hour with a standard deviation of 5.

9 miles per hour. What is the probability that a randomly selected car is violating the speed limit of 50 miles per hour?
0.43

0.50

0.51

0.57
Mathematics
1 answer:
Oliga [24]3 years ago
5 0

Answer: 0.57

Step-by-step explanation:

Given : The speed of cars on a stretch of road is normally distributed .

Population Mean = \mu=51\text{ miles per hour}

Standard deviation : \sigma= 5.9\text{ miles per hour}

Let x be the random variable that represents the speed of cars on a stretch of road .

z-score : z=\dfrac{x-\mu}{\sigma}

For x= 50.

z=\dfrac{50-51}{5.9}\approx-0.17

By using the standard normal distribution table ,

The probability that a randomly selected car is violating the speed limit of 50 miles per hour :-

P(x>50)=1-P(x\leq50)=1-P(z\leq-0.17)\\\\=1- 0.4325051=0.5674949\approx0.57\\

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Volgvan

Answer:

So the correct option is First one

i.e \dfrac{9\pi}{A}=\dfrac{90}{360}

Step-by-step explanation:

Given:

Area of Shaded part = 9 π square feet

To Find :

Area of Circle = ?

Solution:

90 degree center angle is equivalent to an area of 9 Π  square feet

So, 360 degree center is equivalent to area A which is the area of the complete circle.

So the Ratio will be

\dfrac{90}{9\pi} =\dfrac{360}{A}

Setting the given statements in proportion:

\dfrac{90}{9\pi} =\dfrac{360}{A}

On solving we get the required

\dfrac{9\pi}{A} =\dfrac{90}{360}

So the correct option is First one

i.e \dfrac{9\pi}{A}=\dfrac{90}{360}

Alternate Method:

Shaded part is of 90°

Area of Shaded part = 9 π square feet

And Full Circle is of 360° that is 4 sector of 90°

\textrm{Area of Circle}=4\times (Shaded\ part)

\textrm{Area of Circle}=4\times 9\pi

\textrm{Area of Circle}=36\pi

So the correct option is First one

i.e \dfrac{9\pi}{A}=\dfrac{90}{360}

On solving this we get

A=36\pi\ feet^{2}

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2 years ago
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vivado [14]

Answer:

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3 years ago
Suppose you received a score of 95 out of 100 on exam 1 . The mean was 79 and the standard deviation was 8 . If your score on ex
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Answer:

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Step-by-step explanation:

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<u>Z = (X - μ)/σ</u>

Where X = score obtained

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           σ = standard deviation

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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