2 years ago

In AWXY, X = 700 cm, w = 710 cm and Angle W= 249. Find all possible values of Angle X, to the nearest 10th of a degree.

Mathematics

1 answer:

LekaFEV [45]2 years ago

4 0

Answer:

Step-by-step explanation:

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Sedbober [7]

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$\sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n$

Step-by-step explanation:

Given expression : $\sum_{n=3}^{20}(n(n+1))$

Solving further :

$\Rightarrow \sum_{n=3}^{20}(n^2+n)$

$\Rightarrow \sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n$

So, $\sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n$

So, The given expression is equivalent to Option A

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In AWXY, X = 700 cm, w = 710 cm and Angle W= 249. Find all possible values of Angle X, to the nearest 10th of a degree.​

In AWXY, X = 700 cm, w = 710 cm and Angle W= 249. Find all possible values of Angle X, to the nearest 10th of a degree.