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3 years ago

HEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEELP!

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

8 0

Olá

Answer:

(5x)³=

(5x) ao cubo

5.5.5=125X³

2(x+5)= 2x+10

2x=10

x=10/2

X=5

2x+5= 2x - 5 = 0

2x = 0 + 5

2x = 5

x = 5/2

3x-5= 3x= +5

X= 5/3 or X= 1,6

5+2x= 2x=-5

X= -5/2

5+x²= x²+5 a=1 b= 5 c=0

5²-4.1.0 (corta,pois -4.1.0=0)

=25

x= -b +/- raíz de bhaskara/ 2.a

x=-5 +/- 5/2

x'= 0/2=0

x"= -10/2= -5

5-3x= 3x=-5

X= -5/3

5x³ = 0 a=5 b= 0 c=0

0²-4.5.0

= 0 (duas raízes reais e iguais)

x'= 0

x"= 0

Espero ajudar♥

babymother [125]3 years ago

3 0

Answer:

Five more than the square of a number= 5 + x²

Five more than twice a number = 5 + 2x

Five less than the product of 3 and a number = 3x - 5

Five less the product of 3 and a number = 5 -3x

Twice the sum of a number and 5 = 2(x + 5)

The sum of twice a number and 5 = 2x + 5

The product of a cube of a number and 5= 5x³

The cube of the product of 5 and a number= (5x)³

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You have 100 yards of fencing available to create an enclosure for farm animals. As the

Sunny_sXe [5.5K]

1. area of a pentagon when 1 side is x is $\frac{x^2}{4}\sqrt{5(5+2\sqrt{5})}$
so if perimiter is 100 then one side is 100/5 or 20
area will be $\frac{20^2}{4}\sqrt{5(5+2\sqrt{5})}$ ≈688.2 square yards

2. area of a hexagon when 1 side is length x is $\frac{3x^2\sqrt{3}}{2}$
so if permiter is 100 then length of one side is 100/6 or about 16.666666666666
the area will be $\frac{3(16.6666666)^2\sqrt{3}}{2}$ ≈721.7 square yards

3. area of a regular octagon with side lenghts x is $2(1+\sqrt{2})x^2$
so if 8 sides then side length of each is 100/8 or 12.5
area will be $2(1+\sqrt{2})12.5^2$ ≈754.4 square yards

octagon wil have most space
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3 years ago

What is the variable y in w= x y/z?

AleksAgata [21]

Multiply by z to get
wz = xy
divide by x
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2 years ago

About 62% of the human body is composed of water. Write this percent as a fraction in simplest form.

aleksklad [387]

31/50 by the way I love how some people realize so many people answered this question already and decide they should add something that is totally not necessary.

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3 years ago

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Mashutka [201]

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3 years ago

Write an equation for the line passing through the points (-5,15) and (20,25). Show how you found your answer.

olasank [31]

The point-slope form:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (-5, 15) and (20, 25). substitute:

$m=\dfrac{25-15}{20-(-5)}=\dfrac{10}{25}=\dfrac{2}{5}\\\\y-15=\dfrac{2}{5}(x-(-5))\\\\y-15=\dfrac{2}{5}(x+5)\qquad|\text{use distributive property}\\\\y-15=\dfrac{2}{5}x+2\qquad|\text{add 15 from both sides}\\\\y=\dfrac{2}{5}x+17\qquad|\text{multiply both sides by 5}\\\\5y=2x+85\qquad|\text{subtract 2x from both sides}\\\\-2x+5y=85\qquad|\text{change the signs}\\\\2x-5y=-85$

Answer:

point-slope form: $y-15=\dfrac{2}{5}(x+5)$

slope-intercept form: $y=\dfrac{2}{5}x+17$

standard form: $2x-5y=-85$

7 0

3 years ago