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2 years ago

HEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEELP!

Mathematics

2 answers:

andreyandreev [35.5K]2 years ago

8 0

Olá

Answer:

(5x)³=

(5x) ao cubo

5.5.5=125X³

2(x+5)= 2x+10

2x=10

x=10/2

X=5

2x+5= 2x - 5 = 0

2x = 0 + 5

2x = 5

x = 5/2

3x-5= 3x= +5

X= 5/3 or X= 1,6

5+2x= 2x=-5

X= -5/2

5+x²= x²+5 a=1 b= 5 c=0

5²-4.1.0 (corta,pois -4.1.0=0)

=25

x= -b +/- raíz de bhaskara/ 2.a

x=-5 +/- 5/2

x'= 0/2=0

x"= -10/2= -5

5-3x= 3x=-5

X= -5/3

5x³ = 0 a=5 b= 0 c=0

0²-4.5.0

= 0 (duas raízes reais e iguais)

x'= 0

x"= 0

Espero ajudar♥

babymother [125]2 years ago

3 0

Answer:

Five more than the square of a number= 5 + x²

Five more than twice a number = 5 + 2x

Five less than the product of 3 and a number = 3x - 5

Five less the product of 3 and a number = 5 -3x

Twice the sum of a number and 5 = 2(x + 5)

The sum of twice a number and 5 = 2x + 5

The product of a cube of a number and 5= 5x³

The cube of the product of 5 and a number= (5x)³

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ololo11 [35]

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2 years ago

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rewona [7]

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Step-by-step explanation:

We simply graph the two functions in the same graph. The solution set to the system is given by the points where the two functions intersect. For this case, the two functions intersect at;

(1,8) and (-3,0)

The solution set is thus; (1,8) and (-3,0)

Check the attachment below;