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Vladimir [108]
3 years ago
13

HEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEELP!

Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
8 0

Olá

Answer:

(5x)³=

(5x) ao cubo  

5.5.5=125X³

2(x+5)= 2x+10

             2x=10

              x=10/2

                X=5

2x+5= 2x - 5 = 0  

2x = 0 + 5  

2x = 5  

x = 5/2

3x-5= 3x= +5

           X= 5/3 or X= 1,6

5+2x= 2x=-5

            X= -5/2

5+x²= x²+5  a=1 b= 5 c=0

5²-4.1.0 (corta,pois -4.1.<u><em>0=0)</em></u>

=25  

x= -b +/- raíz de bhaskara/ 2.a

x=-5 +/- 5/2

x'= 0/2=0

x"=  -10/2= -5

5-3x= 3x=-5

          X= -5/3

5x³ = 0   a=5 b= 0 c=0

0²-4.5.0

= 0 (duas raízes reais e iguais)

x'= 0

x"= 0

Espero ajudar♥

       

             

babymother [125]3 years ago
3 0

Answer:

Five more than the square of a number= 5 + x²

Five more than twice a number = 5 + 2x

Five less than the product of 3 and a number = 3x - 5

Five less the product of 3 and a number = 5 -3x

Twice the sum of a number and 5 = 2(x + 5)

The sum of twice a number and 5 = 2x + 5

The product of a cube of a number and 5= 5x³

The cube of the product of 5 and a number= (5x)³

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7 0
3 years ago
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

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