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kicyunya [14]
3 years ago
6

What is the formula for the nth term of the given sequence? -17, -8, 1

Mathematics
1 answer:
Citrus2011 [14]3 years ago
4 0

Answer:

The n^{th} term of A.P sequence

tₙ = 9 n - 26

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given sequence

                   - 17 , -8 , 1 .......

first term   = -17

Second term =  - 8

The difference of first two terms

                        d = - 8 -(-17) = -8+17 = <em>9</em>

The difference of next two terms

                        d = 1 - (-8) = 1+8 =   9

∴ The given sequence is  in A.P ( Arthimetic progression)

<u><em>Step(ii):-</em></u>

The n^{th} term of A.P sequence

                t_{n}  = a + ( n-1 ) d

Given a = - 17 and  d = 9

                t_{n}  = -17 + ( n-1 ) 9 = - 17 + 9 n -9 = 9 n - 26

<u><em>Final answer</em></u>:-

The n^{th} term of A.P sequence

tₙ = 9 n - 26

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Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
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(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

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Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
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