The congruence theorem that can be used to prove △LON ≅ △LMN is SSS. ASA. SAS. HL.
2 answers:
Answer:
The correct option is SSS (Side-Side-Side) Theorem
Step-by-step explanation:
The question is incomplete because the diagrams of ΔLON and ΔLMN are not given. I have attached the diagram of both triangles below for better understanding of the question.
Consider the diagram attached below. We have to find the congruence theorem which can be used to prove that ΔLON ≅ ΔLMN
We can see in the diagram that both triangle have a common side that is LN. It means 1 side of both triangles is congruent because LN≅LN
Consider the sides ON and MN. Both side have a single bar on them, which means that it is given that both of these side are congruent. Hence ON≅MN
Consider the sides LO and LM. Both side have a double bars on them, which means that it is given that both of these side are also congruent. Hence LO≅LM
SSS theorem states that if all sides of the triangles are congruent, then the triangles themselves are also congruent, which is the same case in this question
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Answer:
The size of the cardboard should be
Step-by-step explanation:
The diagram for this question is shown on the first uploaded image
The volume of the box is
The length and the Width of the card is
L = W = Z
From the question we are told that 7 in squares were cut from each corner
So the length and the width of the box would be
L = W = (Z - 7)
And the height would be H = 7 in
Mathematically the volume of the box can be represented as
So the Volume would be
Substituting values
=>
Since the rotation is about the y-axis, I'll integrate by dy.
so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check
so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.