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2 years ago

PLEASE HELP IT IS DUE RIGHT NOW!!! WILL MARK BRAINLIEST!!!!!

Mathematics

2 answers:

scoundrel [369]2 years ago

8 0

Answer:

(1,-7)

Step-by-step explanation:

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kramer2 years ago

3 0

Answer:

1, -7

Step-by-step explanation:

-2x-5=-x-6

x=6-5

x=1

y=-2x-5=-2-5=-7

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Evaluate the expression <br><br><br><br>please HELP

mamaluj [8]

w+5=8 because 3+5=8 so

w+5=9 because we put w as 4

w +5=10 so w is 5

6 0

3 years ago

Thee population of a town, P(t), is 2000 in the year 2010. Every year, it increases by 1.5%. Write an equation for the populatio

steposvetlana [31]

Given:

In 2010, the population of a town = 2000

Every year, it increase by 1.5%

To find the equation P(t) which represents the population of this town t years from 2010.

Formula

If a be the original population of a town and it increases by b% every year, after t year the population will be

$a (1+\frac{b}{100} )^{t}$

Now,

Taking, a =2000, b = 1.5 we get,

$P(t) = 2000(1+\frac{1.5}{100} )^{t}$

or, $P(t) = 2000(1+0.015)^{t}$

Hence,

The population of this town t years from 2010 P(t) = $2000(1+0.015)^{t}$ , Option D.

7 0

3 years ago

❊ Simplify :

Nataliya [291]

To simplify the given expression .

$\red{\frak{Given}}\Bigg\{ \sf \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 }$

$\rule{200}4$

$\sf\longrightarrow \small \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 } \\\\\\\sf\longrightarrow \small \dfrac{ x-1}{x^2-x -2x +2} +\dfrac{ x-2}{x^2-3x-2x+6} +\dfrac{ x -5}{x^2-5x -3x + 15 } \\\\\\\sf\longrightarrow\small \dfrac{ x -1}{ x ( x - 1) -2(x-1) } +\dfrac{ x-2}{x ( x -3) -2( x -3)} +\dfrac{ x -5}{ x(x-5) -3( x -5) } \\\\\\\sf\longrightarrow \small \dfrac{ x -1}{ ( x-2) (x-1) } +\dfrac{ x-2}{( x -2)(x-3) } +\dfrac{ x -5}{ (x-3)(x-5) } \\\\\\\sf\longrightarrow\small \dfrac{ 1}{ x-2} +\dfrac{ 1}{ x -3} +\dfrac{1}{ x -3} \\\\\\\sf\longrightarrow \small \dfrac{1}{x-2} +\dfrac{2}{x-3} \\\\\\\sf\longrightarrow \small \dfrac{ x-3 +2(x-2)}{ ( x -3)(x-2) } \\\\\\\sf\longrightarrow \small \dfrac{ x - 3 +2x -4 }{ (x-3)(x-2) } \\\\\\\sf\longrightarrow \underset{\blue{\sf Required \ Answer }}{\underbrace{\boxed{\pink{\frak{ \dfrac{ 3x -7}{ ( x -2)(x-3) } }}}}}$