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2 years ago

5

Find the value of xFind the value of xFind the value of x

1 answer:

Natali [406]2 years ago

3 0

Answer:

x = 11

Step-by-step explanation:

$\frac{x + 2}{6} - \bigg( \frac{11 -x }{3} - \frac{1}{4} \bigg) = \frac{3x - 4}{12} \\ \\ \frac{2(x + 2)}{2 \times 6} - \bigg( \frac{4(11 - x) - 1 \times 3}{3 \times 4} \bigg) = \frac{3x - 4}{12} \\ \\ \frac{2x + 4}{12} - \bigg( \frac{4 4 - 4x- 3}{12} \bigg) = \frac{3x - 4}{12} \\ \\ \frac{2x + 4}{12} - \bigg( \frac{41 - 4x}{12} \bigg) = \frac{3x - 4}{12} \\ \\ \frac{2x + 4 - 41 + 4x}{ \cancel{12}} = \frac{3x - 4}{ \cancel{12}} \\ \\ 6x - 37 = 3x - 4 \\ \\ 6x - 3x = 37 - 4 \\ \\ 3x = 33 \\ \\ x = \frac{33}{3} \\ \\ \huge \red{ \boxed{ x = 11}}$

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Answer:

(a)

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(b)

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(c)

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(d)

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Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

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we get

$5^{-3}=\frac{1}{5^3}$

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(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

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Answer:

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