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Masja [62]
3 years ago
15

A plank 6m long leans against a vertical wall so that the foot of the plank is 4m away from the wall. A lizard climbs 2m up the

plank. Calculate the horizontal distance between the lizard and the wall.
Mathematics
1 answer:
Lynna [10]3 years ago
7 0

Answer: \dfrac{8}{3}\ m

Step-by-step explanation:

Given

Length of the plank is 6\ m

Foot of the flank is 4\ m away from the wall

Lizard climbs 2 m up the wall

from the figure, the two triangles are similar

\therefore \dfrac{2}{6}=\dfrac{x}{4}\\\\\Rightarrow x=4\times \dfrac{2}{6}\\\\\Rightarrow x=\dfrac{4}{3}\ m

So, the distance from the wall is

\Rightarrow 4-x\\\\\Rightarrow 4-\dfrac{4}{3}\\\\\Rightarrow \dfrac{8}{3}\ m

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| | 6 | 4

× | | 1 | 6

| 3 | 8 | 4

| 6 | 4 | 0

1 | 0 | 2 | 4:

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