Circumference one = (2R)*pi let that value be 2x
C second = 5x = (2R)*pi * 5 / 2 = (5R)*pi
So Radius one / Radius two = 2 / 5
Area1:Area2=pi(2R)^2:pi(5R)^2=pi(4R^2):pi(25R^2), pi cancel out we get
4R^2:25R^2, now R^2 cancel out and we get ratio of
4:25
If 3z=2z+5 and z=5, then you’d just plug the 5 in.
3(5)=2(5)+5 —> 15=10+5 —> 15=15
This statement is TRUE because 15 does equal 15.
I hope this helps. :)
Answer:
x = 4
Step-by-step explanation:
The equation comes out to be:
3x + 11 = 5x + 3
Move the <u>variables</u> to the left-hand side and change its sign
And move the <u>constant</u> to the right-hand side and change its sign:
3x - 5x = 3 - 11
Combine like terms to get:
-2x = -8
Isolate x by dividing -2 on both sides:
-2x/-2 = -8/-2
x = 4
-8(3 - s) = 32
So you expand the brackets
-24 + 8s = 32
And then solve
+ 24
8s = 56
÷ 8
s = 7
Hope this helps!