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erik [133]
3 years ago
15

Denise bought a box of 560 pieces of candy.4/5 of the pieces of the candy were fruity and 1/4 of the remaining pieces of candy w

ere mint.How many of candy of the other flavors were there?
Mathematics
1 answer:
Liula [17]3 years ago
8 0

Answer:

<em>Number of Other flavor candy is 84.</em>

Step-by-step explanation:

Given that

A total of 560 pieces of candy are there in the box.

\frac{4}{5} of the pieces are fruity.

Number of Fruity pieces:

\dfrac{4}{5} \times 560\\\Rightarrow 4 \times 112 =448

Now, remaining pieces = Total pieces - Fruity pieces

remaining pieces = 560 - 448 = 112

Also given that \frac{1}4 of the remaining pieces are mind.

Number of mint pieces:

\dfrac{1}{4}\times 112 = 28

Other flavors remaining = Total pieces - Fruity pieces - Mint pieces

Other flavors remaining = 560 - 448 - 28

Other flavors remaining = 112 - 28 = <em>84</em>

<em>Number of Other flavor candy is 84.</em>

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Answer:

it equals 8458

Step-by-step explanation:

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3 years ago
Find the x-intercepts of the parabola with vertex (1,1) and y-intercept (0,-3). Write your answer in this form (x of 1 , y of 1)
Vikki [24]
Remember that the vertex form of a parabola or quadratic equation is:

y=a(x-h)^2+k, where (h,k) is the "vertex" which is the maximum or minimum point of the parabola  (and a is half the acceleration of the of the function, but that is maybe too much :P)

In this case we are given that the vertex is (1,1) so we have:

y=a(x-1)^2+1, and then we are told that there is a point (0,-3) so we can say:

-3=a(0-1)^2+1

-3=a+1

-4=a so our complete equation in vertex form is:

y=-4(x-1)^2+1

Now you wish to know where the x-intercepts are.  x-intercepts are when the graph touches the x-axis, ie, when y=0 so

0=-4(x-1)^2+1  add 4(x-1)^2 to both sides

4(x-1)^2=1  divide both sides by 4

(x-1)^2=1/4  take the square root of both sides

x-1=±√(1/4)  which is equal to

x-1=±1/2  add 1 to both sides

x=1±1/2

So x=0.5 and 1.5, thus the x-intercept points are:

(0.5, 0) and (1.5, 0)  or if you like fractions:

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4 0
3 years ago
Please help with this. I only need help with the first question I have the second one figured out,
lutik1710 [3]

Answer:

m∠WZX = 41°

Step-by-step explanation:

diagonals bisect angles and opposite angles are congruent

therefore, ∠WXY ≅ ∠WZY

∠WZY must equal [360 - 2(68)] ÷ 2 which equals 112°

If ∠WXZ = 71° then so does ∠XZY

Which means that ∠WZX must equal 112-71 which is 41°

6 0
3 years ago
Read 2 more answers
None of my answers work on this? Either somethings not right or what..
Pavel [41]
Answer is below this comment :D

8 0
2 years ago
A^2(64a^2-3)/3=27-4a^2/4
frutty [35]
The answer is a = 3/4 = 0.75

First get rid of the paranthesis,
{a}^{2} (64 {a}^{2}  - 3) = 64 {a}^{4} -  3 {a}^{2}
Then set the denominators equal:
\frac{ 256 {a}^{4}  - 12 {a}^{2}}{12}  =  \frac{81 - 12 {a}^{2} }{12}
Then remove the denominators and solve:
256 {a}^{4}  - 12 {a}^{2}  = 81 - 12 {a}^{2}
Eliminate -12a^2 by adding 12a^2 to both sides:
256 {a}^{4}  = 81
Take the fourth root of them or take the square root twice:
\sqrt[4]{256 {a}^{4} }  =  \sqrt[4]{81}   \\  4a = 3
Divide both sides by 4:
a =  \frac{3}{4}  = 0.75
7 0
2 years ago
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