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Rashid [163]
3 years ago
11

Please help me thank you.

Mathematics
2 answers:
coldgirl [10]3 years ago
7 0
The value of x would be 4m
spayn [35]3 years ago
7 0
Volume = 1/2πr²h

12π = 1/3π(3)²(x)
12π = 3πx
x = 12π ÷ 3π
x = 4

Answer: x = 4m
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At time t=0 hours, a tank contains 3000 litres of water. Water leaks from the tank. At the end of every hour there is x% less wa
Margaret [11]

Answer:

x = 2; K = 0.98

Step-by-step explanation:

At time, t = 0, Volume of Water = 3,000 litres

After t hours , the Volume of water in the tank = Vt

At the end of every hour there is a x% less water in the tank then at the start of the hour

After 1 hour, volume of water left Vt = V1

V1 = 3,000 - 3000 × (x/100)

V1 = 3,000 - 30x

After 2 hours, Volume of water left is V2

V2 = (3,000 - 30 x) - (3,000 - 30 x) × (x/100)

V2 = (3,000 - 30 x) - (3000x - 30x²)/100

V2 = {100(3000 - 30x) - x(3000 - 30x)} /100

V2 = {(3000 - 30x)(100 - x)}/100

Recall, V2 = 2881.2

Therefore

{(3000 - 30x)(100 - x)}/100 = 2881.2

(3000 - 30x)(100 - x) = 288120

300000 - 3000 x - 3000 x + 30 x² = 288120

30 x ² - 6000 x + 11880 = 0

Dividing both sides by 30

x² - 200 x + 396=0

Factorizing:

(x -198)(x-2) = 0

x = 198 or x = 2

Since the percentage by which the water reduces cannot be greater than 100, x = 2 is chosen.

Step 2: Solving for k

Given that Vt=KtV0

K = Vt/V0

At t = 1

V1 = 3000 - 30x

V1 = 3000 - 30 × 2

V1 = 3000 - 60

V1 = 2940

K = 2940/3000

K = 0.98

5 0
3 years ago
Someone please help me will give BRAILIEST!!!!!!
Kipish [7]
The answer would be 15
6 0
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Read 2 more answers
Find f'(0.3) for f(x)= the integral from 0 to x of arccos(t)dt
Lady_Fox [76]
\bf \textit{using the 2nd fundamental theorem of calculus}\\\\
\cfrac{dy}{dx}\displaystyle \left[ \int\limits_{0}^{x}\ cos^{-1}(t)dt \right]\implies cos^{-1}(x)
\\\\\\
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now.. 0.3 is just a value...we'e assuming Radians for the inverse cosine, so, if you check, make sure your calculator is in Radian mode
8 0
3 years ago
Which of the following rational functions is graphed below?
Zepler [3.9K]

Answer:

  D.  F(x) = 1/(x +5)²

Step-by-step explanation:

The vertical asymptote at x=-5 tells you that x=-5 will be a zero of the denominator. The only equation with a denominator factor of (x+5) is ...

  F(x) = 1/(x +5)²

_____

<em>Additional comment</em>

The fact that the value of F(x) does not change sign at the vertical asymptote tells you the denominator factor will be of even degree. That is taken for granted here, as all denominators are squares in the answer choices.

3 0
2 years ago
30 POINTS FOR ANSWER!!<br> 2 numbers sum 120 and product 400<br> INSTANT ANSWER NEEDED
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I think the problem is
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