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2 years ago

9

Again you don’t need to answer all of them but if you can do some that would be wonderful!

2 answers:

Maru [420]2 years ago

8 0

Answer:

17) x=7

18) x= -26

19) x= -8

20) x= 6

Step-by-step explanation:

17) is congruent

18) is supplementary

19) is congruent

20) is congruent

Akimi4 [234]2 years ago

4 0

Answer:

Q17. 6x+8=50 (alt angles, u//v)

6x=50-8

=42

x=42÷6

=7

Q18. 80°+x+106°=180° (int angles, u//v)

x+186°=180°

x=180°-186°

=-6

Q19. x+68=60 (vert opp angles)

x=60-68

=-8

Q20. 20x=120°

x=120÷20

=10

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I need help asap!!!!!!!!!!!!!!!!!!!!

madreJ [45]

Answer:

# 2 is correct :)

Step-by-step explanation:

8 0

2 years ago

Solve the equation and enter the value of x below 2(x+6)=-10

malfutka [58]

Answer:

$\huge \boxed{x=-11}$

Step-by-step explanation:

First, divide by 2 from both sides of equation.

$\displaystyle \frac{2(x+6)}{2}=\frac{-10}{2}$

Then, solve.

$\displaystyle x+6=-5$

Subtract by 6 from both sides of equation.

$\displaystyle x+6-6=-5-6$

Solve to find the answer.

$\displaystyle x=-11$ , which is our answer.

6 0

3 years ago

Can you help me with my math questions

GrogVix [38]

$p^2+2(7)p+7^2=(p+7)^2$

Justification:

Given: $p^2+14p+49$

Split the middle term;

$=p^2+7p+7p+49$

Factor:

$=p(p+7)+7(p+7)$

$=(p+7)(p+7)$

$=(p+7)^2$

QUESTION 3a

The given expression for the area of the rectangle is $36x^2-12x+1$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$36x^2-12x+1=289$

$\Rightarrow (6x-1)^2=289$

$\Rightarrow (6x-1)(6x-1)=289$

$\Rightarrow l=(6x-1),w=(6x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow (6x-1)=\pm \sqrt{289}$

$\Rightarrow (6x-1)=\pm 17$

$\Rightarrow 6x=1\pm 17$

$\Rightarrow 6x=18 \:or\:6x=-16$

$\Rightarrow x=3 \:or\:x=-\frac{2}{3}$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=(6(3)-1)=17,w=6(3)-1=17$

QUESTION 3b

The given expression for the area of the rectangle is $25x^2-50x+25$ .

This is equal to the indicated area which is $1225\;in^2$

This implies that

$25x^2-50x+25=1225$

$25(x^2-2x+1)=1225$

$(5(x-1))^2=35^2$

$5(x-1)5(x-1)=49$

$\Rightarrow l=5(x-1),w=5(x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow 5(x-1)=\pm \sqrt{1225}$

$\Rightarrow 5(x-1)=\pm 35$

$\Rightarrow x=1\pm 7$

$\Rightarrow x=8 \:or\:x=-6$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=5(8-1)=35,w=5(8-1)=35$

QUESTION 3c

The given expression for the area of the rectangle is $49x^2-56x+16$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$49x^2-56x+16=289$

$(7x-4)^2=289$

$(7x-4)(7x-4)=289$

$\Rightarrow l=(7x-4),w=(7x-4)$

Applying the laws of indices gives;

$(7x-4)^2=17^2$

This implies that;

$7x-4=17$

$7x=21$

$x=3in.$

The side length of this rectangle is

$\Rightarrow l=7(3)-4=17\:in.,w=7(3)-4=17\:in.$

Dont forget that the square is also a rectangle.

5 0

3 years ago

Read 2 more answers

Write down the equation for the following expression and then solve it.

Tems11 [23]

Answer:

x = 24

Step-by-step explanation:

x - (3 · 4) = 12

x - 12 = 12

+ 12 + 12

x = 24

6 0

2 years ago

Read 2 more answers

How to find the point slope form with the slope of 3 and the point of -2/6

Levart [38]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:y-6 = 3(x + 2)$

____________________________________

$\large \tt Solution \: :$

Equation of line in point - slope form :

$\qquad \tt \rightarrow \:y-y_1 = m(x - x_1)$

$\tt \:m = slope=3$

$\tt y_1 = y \: \: coordinate \: \: of \: \: point = 6$

$\tt \:x_1 = x \: \: coordinate \: \: of \: \: point = - 2$

Here :

$\qquad \tt \rightarrow \:y - 6 = 3(x - ( - 2))$

$\qquad \tt \rightarrow \:y - 6 = 3(x + 2)$

5 0

1 year ago