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4 years ago

Jonah finds the length of the sides of the quadrilateral

Mathematics

1 answer:

azamat4 years ago

4 0

Answer: Side BC has a length of square root 10 units

Step-by-step explanation: I just took the test

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4x-5y+2x+4+6+9y+7x+2

gtnhenbr [62]

Answer:

$13x+4y+12$

Step-by-step explanation:

Combine all the like terms & then solve:

$(4x+2x+7x)+(-5y+9y)+(4+6+2)$

$13x+4y+12$

4 0

2 years ago

Read 2 more answers

Question 16 (1 point) (04.05 MC) The graph shows a journey in a car. Which of the statements most likely describes the start of

Genrish500 [490]

Answer:

honestly i think it might be (C)

Step-by-step explanation:

4 0

3 years ago

A Shopkeeper

Sergio [31]

Answer:

The cost of bicycle is Rs1000

Step-by-step explanation:

Let x be the cost of bicycle

Total profit gained by the shopkeeper by selling at labelled price = 20%

Suppose he sell the bicycles at at 5% discount

Which means that the total profit he learn after discount will be:

20% -5% = 15%

The shopkeeper earns a profit of 15% if he sells at discount.

Profit gained by shopkeeper is:

15% of x = 15/100 · x

15% of x = 0.15x

Thus the profit gained will be 0.15x. As profit gained is equal to 150, we can say that

0.15x = 150

x = 1000

The cost of bicycle is Rs1000

4 0

3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

3 years ago

Subtract and simplify 20 2/7 - 26/35

marissa [1.9K]

20& 10/35 - 26/35

19& 16/35 simplified to it's fullest.

4 0

3 years ago