Answer:
(edit: nvm I figured it out, here is the answer)
Explanation:
According to the reaction equation:
and by using ICE table:
CN- + H2O ↔ HCN + OH-
initial 0.08 0 0
change -X +X +X
Equ (0.08-X) X X
so from the equilibrium equation, we can get Ka expression
when Ka = [HCN] [OH-]/[CN-]
when Ka = Kw/Kb
= (1 x 10^-14) / (4.9 x 10^-10)
= 2 x 10^-5
So, by substitution:
2 x 10^-5 = X^2 / (0.08 - X)
X= 0.0013
∴ [OH] = X = 0.0013
∴ POH = -㏒[OH]
= -㏒0.0013
= 2.886
∴ PH = 14 - POH
= 14 - 2.886 = 11.11
C. On the left side .. what the chemical uses is always on the left and what it produces is always on the right.
Hdrogyen? Dont take my word on that
Answer:
A. Limiting reactant
Explanation:
Mark me as a brainliest happy po ako sa pag sagot sana tama ako kung mali paki. Comment lang dito kasi solve ako ulit
