Points A, B, C, and D are collinear and positioned in that order. Solve for x then find the length of: AB, BC, and CD, if AB=x+5
, BC=2x+10, CD=4x, and AD=78
1 answer:
Step-by-step explanation:
we can solve this by Adding all points so you said that all are collinear points which means all points are in one line so this is solved as
= X+5+2X+10+4X=78
=7X+15=78. ....collecting like terms
=7x=78-15
=7x=63. divide both sides with 7
=x=9
So now All sides are solved
●AB=x+5
AB=9+5=14
●BC=2X+10=2(9)+10
BC=28
●CD=4X
CD=4(9)
CD=36
so AB+BC+CD=AD
14+28+36=78
True!!
Thanks in Advance
Nahom Wondale
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