Answer:
∠BJK ≅ ∠CFH
Step-by-step explanation:
∆BJK ≅ ∆CFH then we say ∠BJK ≅ ∠CFH
Only when we say ∠BJK ≅ ∠CFH we can say (expand) and speak of lengths by comparing two of each ∠BJA ≅ ∠AFC whilst ∠BK≅ ∠ HC then repeat with∠BKJ ≅ ∠CHF etc.
Answer:
Step-by-step explanation:
I = {a,d,f}
H = {bcc,g}
Intersection of I & H contains elements present in both I and H.
Since there are no common elements, the intersection is a null set, or
I intersect H = { }
The union of I and H contains elements present in either I or H, without repetitions (order is not important in the roster form of set notation)
I union H = {a,d,f,bcc,g}
The remainder would be 9... I hoped I helped!!
Answer:
BC = 40
Step-by-step explanation:
