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ella [17]
3 years ago
5

May someone help, please ? Thank you ♥️

Mathematics
1 answer:
koban [17]3 years ago
3 0
My final answer is (C) because for the side lenghts to be a right triangle, the values of the first and second terms should be equal to the third (a^2 and b^2 =c^2) hope that helped (:
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Factor 6w^4 + w^3 -3w^2
Shtirlitz [24]
6w^4+w³-3w²=w²(6w²+w-3)
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7 0
3 years ago
Factor complete −2x2 + 10x.
mezya [45]

The factors of the quadratic equation is (x + 1) and (x - 6)

Given,

The quadratic equation; -2x² + 10x + 12

We have to find the factors of this equation using quadratic formula;-

Quadratic formula;- \frac{-b(+-)\sqrt{b^{2} -4ac} }{2a}

Here,

a = -2, b = 10 and c = 12

Now,

\frac{-b(+-)\sqrt{b^{2} -4ac} }{2a} = \frac{-10(+-)\sqrt{10^{2} -4 . -2. 12} }{2.-2} = \frac{-10(+-)\sqrt{100 +96} }{-4} = (-10±14) ÷ -4

Solve for,

- 10 + 14 / -4 = -4/4 = -1

That is, (x + 1)

Solve for,

- 10 - 14 / -4 = -24/-4 = 6

That is,  (x - 6)

Therefore, the factors for the given quadratic equation is (x + 1) and (x - 6)

Learn more about quadratic formula here;

brainly.com/question/9300679

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6 0
1 year ago
How to convert 5x^2-60x+200 to vertex form?
Rom4ik [11]
Y=a(x-h)^2+k 

is what vertex form look like. (h,k) is your vertex so in this problem your vertex would be (60,200) 
6 0
2 years ago
Find the midpoint of the line segment with end coordinates of:
Arisa [49]

Answer:

The midpoint of this line segment is (-1.5, -4.5).

Step-by-step explanation:

In finding the midpoint of a line segment we are actually averaging the x- and y-coordinates of the endpoints:

                                             -2 -1

x-coordinate of midpoint = --------- = -3/2 = -1.5

                                                 2

                                              -4 -5

y-coordinate of midpoint = ---------- = -4.5

                                                   2

The midpoint of this line segment is (-1.5, -4.5).

5 0
2 years ago
A researcher records the repair cost for 8 randomly selected washers. A sample mean of $60.46 and standard deviation of $18.36 a
Anuta_ua [19.1K]

Answer:

The critical value is T = 1.895.

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 6

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.895, which is the critical value.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.895\frac{18.36}{\sqrt{8}} = 12.301

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159

The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

8 0
3 years ago
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