Question

5. Solve each of the following equations for the value of x. Show your work.

Answer 1

Answer:

1.answer

3

+

7

=

4

3

3x+7=43

3x+7=43

3

+

7

−

7

=

4

3

−

7

3x+7{\color{#c92786}{-7}}=43{\color{#c92786}{-7}}

3x+7−7=43−7

2

Simplify

Subtract the numbers

Subtract the numbers

3

=

3

6

3x=36

3x=36

3

Divide both sides of the equation by the same term

3

=

3

6

3x=36

3x=36

3

3

=

3

6

3

\frac{3x}{{\color{#c92786}{3}}}=\frac{36}{{\color{#c92786}{3}}}

33x=336

4

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

1

2

x=12

x=12

Solution

=

12

2.answer

हिंदी में खोजें

4x 16 40

How to solve your problem

4

−

1

6

=

4

0

4x-16=40

4x−16=40

Solve

1

Add

1

6

16

16

to both sides of the equation

4

−

1

6

=

4

0

4x-16=40

4x−16=40

4

−

1

6

+

1

6

=

4

0

+

1

6

4x-16+{\color{#c92786}{16}}=40+{\color{#c92786}{16}}

4x−16+16=40+16

2

Simplify

Add the numbers

Add the numbers

4

=

4

0

+

1

6

4x={\color{#c92786}{40}}+{\color{#c92786}{16}}

4x=40+16

4

=

5

6

4x={\color{#c92786}{56}}

4x=56

4

=

5

6

4x=56

4x=56

3

Divide both sides of the equation by the same term

4

=

5

6

4x=56

4x=56

4

4

=

5

6

4

\frac{4x}{{\color{#c92786}{4}}}=\frac{56}{{\color{#c92786}{4}}}

44x=456

4

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

1

4

solution =14

3 .answer

Solution

=

58