Answer:
<h3>1.answer</h3>
3
+
7
=
4
3
3x+7=43
3x+7=43
3
+
7
−
7
=
4
3
−
7
3x+7{\color{#c92786}{-7}}=43{\color{#c92786}{-7}}
3x+7−7=43−7
2
Simplify
Subtract the numbers
Subtract the numbers
3
=
3
6
3x=36
3x=36
3
Divide both sides of the equation by the same term
3
=
3
6
3x=36
3x=36
3
3
=
3
6
3
\frac{3x}{{\color{#c92786}{3}}}=\frac{36}{{\color{#c92786}{3}}}
33x=336
4
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
1
2
x=12
x=12
Solution
=
12
<h2>2.answer</h2>
हिंदी में खोजें
4x 16 40
How to solve your problem
4
−
1
6
=
4
0
4x-16=40
4x−16=40
Solve
1
Add
1
6
16
16
to both sides of the equation
4
−
1
6
=
4
0
4x-16=40
4x−16=40
4
−
1
6
+
1
6
=
4
0
+
1
6
4x-16+{\color{#c92786}{16}}=40+{\color{#c92786}{16}}
4x−16+16=40+16
2
Simplify
Add the numbers
Add the numbers
4
=
4
0
+
1
6
4x={\color{#c92786}{40}}+{\color{#c92786}{16}}
4x=40+16
4
=
5
6
4x={\color{#c92786}{56}}
4x=56
4
=
5
6
4x=56
4x=56
3
Divide both sides of the equation by the same term
4
=
5
6
4x=56
4x=56
4
4
=
5
6
4
\frac{4x}{{\color{#c92786}{4}}}=\frac{56}{{\color{#c92786}{4}}}
44x=456
4
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
1
4
solution =14
<h2>3 .answer</h2>
Solution
=
58
