Given: F(x) = 2x - 4; GX) = 3x + 2; Hpx)=x2
Find FG H(2)
0 121
27
071
2 answers:
Answer
24
Explanation
The format of the question is convoluted, I will assume you mean:
F(x) = 2x - 4
G(x) = 3x + 2
H(x) = x^2
And you want to find FGH(2) ?
1) To evaluate H(2), substitute
x = 2 into the function H(x) = x^2
H(2) = 2^2 = 4
2) To evaluate G(H(2)) substitute
x = 4 (since this is value obtained from H(2)) into the function
G(x) = 3x + 2
G(4) = 12 + 2 = 14
3) To evaluate F(G(4)) substitute x = 14 into the function F(x) = 2x - 4
F(14) = 28 - 4 = 24
Answer:
FG H(2) = F*G*H(2) = 0
Step-by-step explanation:
Your F(x) = 2x - 4; GX) = 3x + 2; Hpx)=x2 requires a bit of guesswork for the reader to understand it. I believe you meant:
F(x) = 2x - 4; G(X) = 3x + 2; H(x)=x2 Find FG H(2)
First find F(2): f(2) = 2(2) - 4 = 0
Because this multiplicand is zero, further multiplication will result in zero also. Thus, the final answer is zero (0).
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