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Vilka [71]
4 years ago
9

-13x-2=-10x-2 solve for x

Mathematics
2 answers:
Butoxors [25]4 years ago
6 0

Answer:

-3x=0 or 3x=0

Step-by-step explanation:

Sidana [21]4 years ago
4 0

Answer: x = 0

Step-by-step explanation:

-13x - 2 = -10x - 2

-13x + 10x = -2 + 2

-3x = 0

x = 0

Answer: x = 0

<h2><em>Spymore</em></h2>
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Answer:

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Step-by-step explanation:

* Look to the attached file

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4 0
3 years ago
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Which statement about the planes is true?
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3 years ago
Tina covers the floor of a room with carpeting. She uses carpet squares that measure one foot on each side. How many carpet squa
gizmo_the_mogwai [7]

Answer:

She need <u>96 square feet</u> carpet to cover the room.

Step-by-step explanation:

Given:

Tina covers the floor of a room with carpeting. She uses carpet squares that measure one foot on each side.

Now, to find carpet squares does she need to cover a room that 8 feet wide by 12 feet long.

So, the dimensions of room are:

Length = 12 feet.

Width = 8 feet.

Now, getting the area by putting formula:

<u><em>Area of room = Length × width</em></u>

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3 0
3 years ago
For the polynomial below, -2 is a zero.
Harlamova29_29 [7]

Answer:

Step-by-step explanation:

please note -2 is not a zero ,it should be 2 is a zero.

by synthetic division

2|  1  4 -10 -4

  |      2  12  4

  |----------------

     1  6   2  | 0

x²+6x+2=0

x=\frac{-6 \pm \sqrt{36-8} }{2} \\or~x=\frac{-6 \pm2\sqrt{7} }{2} \\or ~x=-3\pm \sqrt{7} \\h(x)=(x-2)(x^2+6x+2)=(x-2)(x-3+\sqrt{7} )(x-3-\sqrt{7})

7 0
3 years ago
the figure below shows a circle centre of radius 10 cm the chord PQ=16cm calculate the area of the shaded region​
m_a_m_a [10]

Step-by-step explanation:

OPQ originally forms a sector, the formula for sector is

\frac{x}{360} \pi {r}^{2}

where x is the degrees of rotation between the two radii.

We know three sides length and is trying to find an angle between the radii so we can use law of cosines which states that

16 =  \sqrt{10 {}^{2} + 10 {}^{2}   - 2(100) \times  \cos(o) }

This isn't the standard formula, it's for this problem

16 =  \sqrt{200 - 200 \times  \cos(o) }

16 =  \sqrt{200  - 200 \cos(o) }

256 = 200 - 200 \cos(o)

56 =  - 200 \cos(o)

-  \frac{7}{25}  =  \cos(o)

\cos {}^{ - 1} (  - \frac{7}{25} )  =  \cos {}^{ - 1} ( \cos(o) )

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So we found our angle of rotation, which is 106.26

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Now let find the area of triangle, we can use Heron formula,

The area of a triangle is

\sqrt{s(s - a)(s - b)(s - c)}

where s is the semi-perimeter.

To find s, add all the side lengths up, 10,10,16 and divide it by 2.

Which is

\frac{36}{2}  = 18

\sqrt{18(18 - 10)(18 - 10)(18 - 16)}

\sqrt{18(8)(8)(2)}

\sqrt{(36)(64)}

6  \times 8 = 48

So our area of the triangle is 48. Now, to find the shaded area subtract the main area,( the sector of the circle) by the area of the triangle so we get

\frac{10626}{360}  - 48

Which is an approximate or

44.73

6 0
2 years ago
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