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3 years ago

Can you find the perimeter of rectangle if you are given juat the measure of two sides?

1 answer:

6 0

It depends, if the two sides given are adjacent to each other then yes. but you are given two opposite sides then no, because you don't know the length of one of the sides, thus not being able to calculate the perimeter

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1. Name three examples of each of the types of properties of matter:

uysha [10]

Intensive properties and extensive properties are types of physical properties of matter. The terms intensive and extensive were first described by physical chemist and physicist Richard C. Tolman in 1917. Here's a look at what intensive and extensive properties are, examples of them, and how to tell them apart.

Intensive Properties

Intensive properties are bulk properties, which means they do not depend on the amount of matter that is present. Examples of intensive properties include:

Boiling point

Density

State of matter

Color

Melting point

Odor

Temperature

Refractive Index

Luster

Hardness

Ductility

Malleability

Intensive properties can be used to help identify a sample because these characteristics do not depend on the amount of sample, nor do they change according to conditions.

Extensive Properties

Extensive properties do depend on the amount of matter that is present. An extensive property is considered additive for subsystems. Examples of extensive properties include:

Volume

Mass

Size

Weight

Length

The ratio between two extensive properties is an intensive property. For example, mass and volume are extensive properties, but their ratio (density) is an intensive property of matter.

While extensive properties are great for describing a sample, they aren't very helpful identifying it because they can change according to sample size or conditions.

Way to Tell Intensive and Extensive Properties Apart

One easy way to tell whether a physical property is intensive or extensive is to take two identical samples of a substance and put them together. If this doubles the property (e.g., twice the mass, twice as long), it's an extensive property. If the property is unchanged by altering the sample size, it's an intensive property.

6 0

3 years ago

(High points) please solve with explanation

AysviL [449]

Answer:

The area and the perimeter of the picture are:

Area = 160 cm^2
Perimeter = 67.31 cm

Step-by-step explanation:

To find the area of that figure, you can find the area how if it was a rectangle and next subtract the area of the triangle in the upper part. The area of a rectangle could be found by the next formula:

Area of a rectangle = base * height

As you can see in the picture, the base is 16 cm and the height is 12 cm, then we replace in the formula:

Area of a rectangle = 16 cm * 12 cm
Area of a rectangle = 192 cm^2

Now, we calculate the area of the triangle to subtract to the area we found and obtain the real area, the formula to obtain the area of a triangle is:

Area of a triangle = (base * height) / 2

The height of the triangle is 8 cm, and the base is 8 cm too, because you subtract to the base of the rectangle (16 cm) the measurements in the upper part (16 - 4 - 4 = 8), Now, we replace in the formula:

Area of a triangle = (8 cm * 8 cm) / 2
Area of a triangle = (64 cm^2) / 2
Area of a triangle = 32 cm^2

We subtract to the found area:

Area of the picture = 192 cm^2 - 32 cm^2
Area of the picture = 160 cm^2

To find the perimeter, you must add all the sides of the picture, but, as you can see, there is a side that doesn't have the measurent, this is the hypotenuse of the triangle used before, but how we know the other sides, we can use Pythagorean theorem:

$a^{2}+b^{2}=c^{2}$

Where:

a = Opposite leg (8 cm)
b = Adjacent leg (8 cm)

So, we replace in the theorem:

$a^{2}+b^{2}=c^{2}$

$(8 cm)^{2}+(8cm)^{2}=c^{2}$ (and we clear c)
$\sqrt{(8 cm)^{2}+(8cm)^{2}} =c$
$\sqrt{64 cm^{2}+64cm^{2}} =c$
$\sqrt{128cm^{2}} =c$
c = 11.3137085 cm
c ≅ 11.31 cm

At last, we add all the sides of the picture begining by the base and going by the left side:

Perimeter of the picture = 16 cm + 12 cm + 4 cm + 11.31 cm + 8 cm + 4 cm + 12 cm
Perimeter of the picture = 67.31 cm approximately.

7 0

3 years ago

PLEASE HURRY IT DO THE NEXT DAY PLZ HELP ME

liberstina [14]

The Bulldogs are least likely to win.

7 0

4 years ago

Read 2 more answers

Can anyone pls help with this ASAP!!! :((

MrRissso [65]

Answer: I believe your answer is C.

7 0

3 years ago

Read 2 more answers

Suppose you have some wolves and some dogs. Dogs are named and wolves are not. If you call a dog it will run to you. A wolf woul

Ira Lisetskai [31]

Answer:

4dogs and no wolves

Step-by-step explanation:

when a dog is taken care of (Trained) it could be let to run free in a definite region.

On a plane with one line we can place two dogs (one dog in each of the regions) and they will not fight as they will be separated by a line, and they will run free.

If we place three lines in general, then we would have four regions where 4 dogs can run free as they are separated by a line so as not to fight.

But for Wolves from the question it is deduced that: A wolf has to be caged all the time and no matter how well you train a wolve, it wont yield to instructions.

With these two, wolves wont be allowed on the plane at all.

8 0

3 years ago