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Greeley [361]
3 years ago
10

Identify the domain and range, then tell if the relation is a function

Mathematics
1 answer:
jekas [21]3 years ago
3 0

Answer:

D:  (-3, 0, 2, 9)

R: (4, 6, 7)

This relationship is a function as there are no two input that have the same output.

Step-by-step explanation:

This relationship is a function as there are no two input that have the same output.

The range is the second output (y-value) which is (4, 6, 7).

The domain is the first element (x-value) of a relation or function which is (-3, 0, 2, 9)

Hope this helps!

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Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x)= 6x^1/3 + 3x^4/3. You must justify
irina [24]

Answer:

x-coordinates of relative extrema = \frac{-1}{2}

x-coordinates of the inflexion points are 0, 1

Step-by-step explanation:

f(x)=6x^{\frac{1}{3}}+3x^{\frac{4}{3}}

Differentiate with respect to x

f'(x)=6\left ( \frac{1}{3} \right )x^{\frac{-2}{3}}+3\left ( \frac{4}{3} \right )x^{\frac{1}{3}}=\frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}

f'(x)=0\Rightarrow \frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}=0\Rightarrow x=\frac{-1}{2}

Differentiate f'(x) with respect to x

f''(x)=2\left ( \frac{-2}{3} \right )x^{\frac{-5}{3}}+\frac{4}{3}x^{\frac{-2}{3}}=\frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}\\f''(x)=0\Rightarrow \frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}=0\Rightarrow x=1

At x = \frac{-1}{2},

f''\left ( \frac{-1}{2} \right )=\frac{4\left ( -1+4\left ( \frac{-1}{2} \right ) \right )}{3\left ( \frac{-1}{2} \right )^{\frac{5}{3}}}>0

We know that if f''(a)>0 then x = a is a point of minima.

So, x=\frac{-1}{2} is a point of minima.

For inflexion points:

Inflexion points are the points at which f''(x) = 0 or f''(x) is not defined.

So, x-coordinates of the inflexion points are 0, 1

7 0
3 years ago
Find the negation of statement <br>2+5=5​
chubhunter [2.5K]

Answer:

Can u mark brainelst plz?

Step-by-step explanation:

x − 1  >  5

x  > − 6

x  +  1  ≥  9

7 0
3 years ago
Urgent please!!! I really don’t understand it, tysm to anyone who can answer thissss :))))
Tomtit [17]

Given:

The frequency distribution table.

To find:

The mean average score on a test.

Solution:

The frequency distribution table is

Marks (x_i)                   Frequency(f_i)                  f_ix_i

     x                                     a                               xa

     y                                     b                               yb

     z                                     c                               zc

  Sum                              a+b+c                          xa+yb+zc

Now, the mean average score on the test is

Mean=\dfrac{\sum f_ix_i}{\sum f_i}

Mean=\dfrac{xa+yb+zc}{a+b+c}

Therefore, the mean average score on the test is \dfrac{xa+yb+zc}{a+b+c}.

3 0
2 years ago
Your family eats at Pizza Hut for dinner. The pizza is $12.99. An order of bread sticks is $5.99. Four drinks were purchased for
Anton [14]

Answer:

$22.87

Step-by-step explanation:

12.99+5.99+2.20=21.18

22.18x.08=1.6944

1.69+22.18=22.87

7 0
3 years ago
Find the slope of the line.
ElenaW [278]

Answer:

-\frac{5}{4}

Step-by-step explanation:

m=\frac{rise}{run}=\frac{-4-1}{1+3}=\frac{-5}{4} =-\frac{5}{4}

Hope this helps.

5 0
2 years ago
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