Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
=========================
next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
=============
2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
Answer:
y = 4000 - 70x
Linear function.
Step-by-step explanation:
Let x = number of weeks.
In 1 week, he withdraws $70.
That means -70 in 1 week.
After the second week, he will have withdrawn 2 times $70, or
-70 × 2
After 3 week, he will have withdrawn -70 × 3
After x weeks, he will have withdrawn $70 × x,or simply -70x.
He starts with 4000, so after x weeks, he has 4000 - 7x.
Let y = the amount of money at week x.
The equation is
y = 4000 - 70x
This is a linear function.
Answer: 0.12 Kilometer
Step-by-step explanation:
120 divided by 1000
B is the answer no capppppp
Answer:
Percent increase = 60%
Percent increase with baggage = 83%
Step-by-step explanation:
Given that:
Old price of the ticket = $210
New price of the ticket = $335
Increase amount =335-210 = $125
Percent increase = 
Percent increase = 
Percent increase = 59.52% = 60%
Additional charges = $125+$50 = $175
Percent increase = 
Percent increase = 83%
Hence,
Percent increase = 60%
Percent increase with baggage = 83%
