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3 years ago

Which is the graph of x – y = 1?

Mathematics

2 answers:

juin [17]3 years ago

4 0

The graph should be where the y intercept is at (0,-1) and the slope is 1.

Please include the graph next time as well

SVETLANKA909090 [29]3 years ago

3 0

Please include the graphs!!!!!

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Find the value of f(2) when f(x) = 4x+2

Sloan [31]

Answer:

the answer is 10

Step-by-step explanation:

f(2) that means the value of x= 2

the substitute x=2 in the 4(2)+2.Replace x with 2

6 0

3 years ago

Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim

Ber [7]

The given function is

$f(x)=4\cos \text{(}\pi x)+1$

The general form of the cosine function is

$y=a\cos (bx+c)+d$

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

$\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}$

The equation of the midline is

$y_{ml}=\frac{y_{\max }+y_{\min }}{2}$

Since the maximum is at the greatest value of cos, which is 1, then

$\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}$

Since the minimum is at the smallest value of cos, which is -1, then

$\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}$

Then substitute them in the equation of the midline

$\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}$

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0

1 year ago

The prism below is made of cubes which measure 1/4 of a centimeter on one side. What is the volume?

goldenfox [79]

Answer:idk

Step-by-step explanation:

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3 years ago

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the art teacher is sending home a total of 3,150 projects before winter break if each of her 150 students had the same number of

Alenkinab [10]

Answer:

21 projects each

Step-by-step explanation:

3150 ÷150

4 0

3 years ago

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the stand

yanalaym [24]

y-y1 = m (x-x1) y+3 = (1/4)(x+4) [using point (x1,y1)] or y–1 = (1/4)(x–12) [using point (x2,y2] [let's use this one since you did] To put this into Standard Form (Ax+By=C), y–1 = (1/4)(x–12) 4y - 4 = x - 12 -x + 4y - 4 = -12 [subtract x from both sides] -x + 4y = -8 [add 4 to both sides] x - 4y = 8 [multiply by (-1) to have x-coefficient positive

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3 years ago

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